对数组中的每一个元素，找出他后面第几个数比自己大

给定一个列表[73, 74, 75, 71, 69, 72, 76, 73]，输出应该是 [1, 1, 4, 2, 1, 1, 0, 0]

public class Test001 {

    public static void main(String[] args) {
        Integer [] arr = new Integer [] {73, 74, 75, 71, 69, 72, 76, 73};
        Stack<Integer> stack = new Stack<Integer>();
        Integer [] res = new Integer[arr.length];
        for(int i = 0 ; i<arr.length ; i++) {
            while(!stack.isEmpty() && arr[i] > arr[stack.peek()]) {
                int index = stack.pop();
                res[index] = i - index;
            }
            stack.push(i);
        }
        while(!stack.isEmpty()) {
            res[stack.pop()] = 0 ;
        }
        Arrays.stream(res).forEach(x -> System.out.print(x + " "));
    }
}