[DP]最长公共子序列

#include <iostream>
#include <vector>
#include <string>
using namespace std;

//最长公共子序列
vector<vector<int> > getdp1(string str1, string str2) {
    vector<vector<int> > dp(str1.length(), vector<int>(str2.length()));
    if (str1.length() == 0 || str2.length() == 0)
        return dp;
    dp[0][0] = str1[0] == str2[0] ? 1 : 0;
    for (int j = 1; j < str2.length(); j ++)  // 为第一行赋值
        dp[0][j] = max(dp[0][j - 1], str1[0] == str2[j] ? 1 : 0);

    for (int i = 1; i < str1.length(); i ++) //为第一列赋值
        dp[i][0] = max(dp[i - 1][0], str2[0] == str1[i] ? 1 : 0);

    for (int i = 1; i < str1.length(); i ++) { //滚动求dp矩阵
        for (int j = 1; j < str2.length(); j ++) {
            dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);
            if (str1[i] == str2[j])
                dp[i][j] = max(dp[i][j], dp[i - 1][j - 1] + 1);
        }
    }
    return dp;
}

string lcse(string str1, string str2) {
    string res = "";
    if (str1.length() == 0 || str2.length() == 0)
        return res;

    vector<vector<int> > dp = getdp1(str1, str2);
    int m = str1.length() - 1;
    int n = str2.length() - 1;
    for (m, n; m >= 0 && n >= 0; ) {
            if (m > 0 &&dp[m][n]  == dp[m - 1][n])
                m --;
            else if (n > 0 && dp[m][n] == dp[m][n - 1])
                n --;
            else {
                res = str1[m] + res;
                m --;
                n --;
            }

    }
    return res;
}

int main()
{
    string str1 = "1A2C3D4B56";
    string str2 = "B1D23CA45B6A";
    vector<vector<int> > dp =  getdp1(str1, str2);
    for (int i = 0; i < dp.size(); i ++) {
        for (int j = 0; j < dp[0].size(); j ++)
            cout<<dp[i][j]<<" ";
        cout<<endl;
    }

    cout<<lcse(str1, str2)<<endl; //输出12C4B6

    return 0;
}
posted @ 2017-09-04 14:42  木白的菜园  阅读(138)  评论(0编辑  收藏  举报