
1 # st='hello kitty {name} is {age}'
2 #
3 # print(st.count('l')) # 统计元素个数
4 # print(st.capitalize()) # 首字母大写
5 # print(st.center(50,'#')) # 居中
6 # print(st.endswith('tty3')) # 判断是否以某个内容结尾
7 # print(st.startswith('he')) # 判断是否以某个内容开头
8 # print(st.expandtabs(tabsize=20))
9 # print(st.find('t')) # 查找到第一个元素,并将索引值返回
10 # print(st.format(name='alex',age=37)) # 格式化输出的另一种方式 待定:?:{}
11 # print(st.format_map({'name':'alex','age':22}))
12 # print(st.index('t'))
13 # print('asd'.isalnum())
14 # print('12632178'.isdecimal())
15 # print('1269999.uuuu'.isnumeric())
16 # print('abc'.isidentifier())
17 # print('Abc'.islower())
18 # print('ABC'.isupper())
19 # print(' e'.isspace())
20 # print('My title'.istitle())
21 # print('My tLtle'.lower())
22 # print('My tLtle'.upper())
23 # print('My tLtle'.swapcase())
24 # print('My tLtle'.ljust(50,'*'))
25 # print('My tLtle'.rjust(50,'*'))
26 # print('\tMy tLtle\n'.strip())
27 # print('\tMy tLtle\n'.lstrip())
28 # print('\tMy tLtle\n'.rstrip())
29 # print('ok')
30 # print('My title title'.replace('itle','lesson',1))
31 # print('My title title'.rfind('t'))
32 # print('My title title'.split('i',1))
33 # print('My title title'.title())
34
35
36 #摘一些重要的字符串方法
37 #1 print(st.count('l'))
38 # print(st.center(50,'#')) # 居中
39 # print(st.startswith('he')) # 判断是否以某个内容开头
40 # print(st.find('t'))
41 # print(st.format(name='alex',age=37)) # 格式化输出的另一种方式 待定:?:{}
42 # print('My tLtle'.lower())
43 # print('My tLtle'.upper())
44 # print('\tMy tLtle\n'.strip())
45 # print('My title title'.replace('itle','lesson',1))
46 # print('My title title'.split('i',1))
1 # a=list()
2 # print(a)
3
4 # dic={'name':'alex'}
5
6 # dic1={}
7 # dic2=dict((('name','alex'),))
8 # print(dic2)
9
10 # dic3=dict([['name','alex'],])
11 # print(dic3)
12
13
14
15
1 # ret2=dic1.setdefault('hobby','girl')
2 # print(dic1)
3 # print(ret2)
4
5
6 # dic3={'age': 18, 'name': 'alex', 'hobby': 'girl'}
7 #
8 # print(dic3['name'])
9 #
10 # print(list(dic3.keys()))
11 # print(list(dic3.values()))
12 # print(list(dic3.items()))
13
14 # li=[1,2,34,4]
15 # li[2]=5
16 # dic3={'age': 18, 'name': 'alex', 'hobby': 'girl'}
17 # dic3['age']=55
18 # print(dic3)
19
20 # dic4={'age': 18, 'name': 'alex', 'hobby': 'girl'}
21 # # dic5={'1':'111','2':'222'}
22 # dic5={'1':'111','name':'222'}
23 #
24 # dic4.update(dic5)
25 # print(dic4)
26 # print(dic5)


16 # dic1={'name':'alex'}
17 # dic1['age']=18
18 # print(dic1)
1 # dic5 = {'name': 'alex', 'age': 18, 'class': 1}
2
3 # dic5.clear() # 清空字典
4 # print(dic5)
5 # del dic5['name'] #删除字典中指定键值对
6 # print(dic5)
7
8
9 # print(dic5.pop('age')) #删除字典中指定键值对,并返回该键值对的值
10 # ret=dic5.pop('age')
11 # print(ret)
12 # print(dic5)
13
14 # a = dic5.popitem() #随机删除某组键值对,并以元组方式返回值
15 # print(a, dic5)
16
17 # del dic5 #删除整个字典
18 # print(dic5)