如何对字符串进行左, 右, 居中对齐str.ljust/rjust/center/format(s,'<20'/'>20'/'^20')

如何对字符串进行左, 右, 居中对齐str.ljust/rjust/center/format(s,’<20’/’>20’/’^20’) 
解决方案: 
使用字符串的str.ljust() str.rjust() str.center() 
使用format() 传递类似’<20’,’>20’,’^20’参数完成任务

 

看下面实例比后面的内容更好使。

%s  --->百分号 跟 s 之间加一个 -5  加负号是左对齐  不加是右对齐

format  --->   大于 小于 能指定 左对齐 还是右对齐

实例：

print('%-10s0'%132)
print('{0: <10}0'.format('963'))

 

 

使用字符串的str.ljust() str.rjust() str.center()

>>> s.ljust(20,"*")
'xyz*****************'
>>> s.rjust(20,"*")
'*****************xyz'
>>> s.center(20,"*")
'********xyz*********'
>>> 

使用format() 传递类似’<20’,’>20’,’^20’参数完成任务

>>> format(s,'*>20')
'*****************xyz'
>>> format(s,'*<20')
'xyz*****************'
>>> format(s,'*^20')
'********xyz*********'
>>>

通过实例来应用字符串对齐

将字典中K/V 按照左对齐方式打印出来

d = {'abcdefeg': 123455, 'xyz': 321, 'uvw': 456}
keymax = max([ len(item) for item in (d.iterkeys())])
valuemax = max([len(str(item)) for item in (d.itervalues())])
valuemax = max(map(len,[str(item) for item in d.itervalues()]))
for k,v in d.iteritems():
    print "%s %s"%(k.ljust(keymax,"*"),str(v).ljust(valuemax,"-"))

abcdefeg 123455
xyz***** 321---
uvw***** 456---

help(str.ljust/rjust/center/fomrat)

Help on method_descriptor:

rjust(...)
    S.rjust(width[, fillchar]) -> string

    Return S right-justified in a string of length width. Padding is
    done using the specified fill character (default is a space)

>>> help(str.center)
Help on method_descriptor:

center(...)
    S.center(width[, fillchar]) -> string

    Return S centered in a string of length width. Padding is
    done using the specified fill character (default is a space)

>>> help(format)
Help on built-in function format in module __builtin__:

format(...)
    format(value[, format_spec]) -> string

    Returns value.__format__(format_spec)
    format_spec defaults to ""