select
        l.lid,
        GROUP_CONCAT(s.NAME) shopname,
        m.realname,
        u.NAME,
        m.phone,
        a.name,
        concat(l.progress,'')
    from
        loan l,
        bank b,
        merchant m,
        bank_user u,
        area a,
        shop s 
    where
        l.bid=b.bid 
        and l.mid=m.mid 
        and l.uid=u.uid  
        and b.aid=a.id 
        and l.lid=s.lid 

    GROUP BY
        l.lid  

shop对loan是多对一,GROUP_CONCAT(s.NAME),可以将一个lid的多个shop.name用“,”拼接起来

字段类型的巧妙转化!
concat(l.progress,'') 将其他类型的progress字段,转化为varchar即String输出!
可避免数据从库中取出时的错误(如TINYINT类型取出后为true/false)

 

 

posted on 2017-05-20 00:02  waytods  阅读(500)  评论(0编辑  收藏  举报