第3章(第四版)C语言程序设计练习
一、例题
1.温度转换(64ºF→17.8ºC)
#include<stdio.h> int main() { float f = 0; float c = 0; scanf_s("%f", &f); printf("摄氏度为:%f\n华氏度为:%f\n", (5.0 / 9) * (f - 32.0),f); }
2.1000存储一年
(1)活期,年利率r1
(2)定期,年利率r2
(3)两次半年定期,年利率r3
求本息和
#include<stdio.h> int main() { float r1 = 0; float r2 = 0; float r3 = 0; scanf_s("%f %f %f", &r1, &r2, &r3); printf("活期%f\n", 1000 * (r1+1)); printf("活期%f\n", 1000 * (r2 + 1)); printf("活期%f\n", 1000 * (r3 / 2.0 + 1)*(r3 / 2.0 + 1)); return 0; }
3.输入大写字母,输出小写字母
#include<stdio.h> int main() { char c1 = 0; printf("请输入大写字母\n"); scanf_s("%c", &c1); printf("输出小写字母为:%c\n输入大写字母为:%c\n", c1 + 32,c1); return 0; }
4.通过三角形边长,求三角形面积
area=√s(s-a)(s-b)(s-c)
s=(a+b+c)/2
#include<stdio.h> #include<math.h> int main() { double a, b, c, s; scanf_s("%lf %lf %lf", &a, &b, &c); s = (a + b + c) / 2; printf("%lf\n", sqrt(s * (s - a) * (s - b) * (s - c))); return 0; }
5.求ax2+bx+c=0方程的根,设b2-4ac>0
#include<stdio.h> #include<math.h> int main() { double a, b, c; double x1, x2,x ; printf("请输入a,b,c:\n"); scanf_s("%lf %lf %lf", &a, &b, &c); if (b * b - 4 * a * c > 0) { x1 = (-b + sqrt(b * b - 4 * a * c)) / (2.0 * a); x2 = (-b - sqrt(b * b - 4 * a * c)) / (2.0 * a); printf("x1=%lfx2=%lf", x1, x2); } else if (b * b - 4 * a * c == 0) { x= -b / (2.0 * a); printf("x=%lf", x); } else { printf("不存在根"); } return 0; }
6.输入BOY,输出BOY
#include<stdio.h> int main() { char a, b, c; a = getchar(); b = getchar(); c = getchar(); putchar(a); putchar(b); putchar(c); return 0; }
二、习题
1.年增长率为9%,10年后增长多少百分比?
p = ( 1 + r ) n
r:年增长率 n:年 p:现在相比的倍速
#include<stdio.h> #include<math.h> int main() { double r, n, p; printf("请输入年增长率(r),年(n)\n"); scanf_s("%lf,%lf", &r, &n); p = pow(1 + r, n); printf("现在相比的倍速(p):%lf\n", p); return 0; }
2.
#include <stdio.h> #include <math.h> int main() { float r5, r3, r2, r1, r0, p, p1, p2, p3, p4, p5; //double r5, r3, r2, r1, r0, p, p1, p2, p3, p4, p5; p = 1000; r5 = 0.0585; r3 = 0.054; r2 = 0.0468; r1 = 0.0414; r0 = 0.0072; p1 = p * (1 + r5 * 5); p2 = p * (1 + 2 * r2) * (1 + 3 * r3); p3 = p * (1 + 3 * r3) * (1 + 2 * r2); p4 = p * pow(1.0 + r1, 5); p5 = p * pow(1.0 + r0 / 4, 4 * 5); printf("一次存5年期p1:=%f\n", p1); //printf("p1=%10.2f\n", p1); printf("先存2年期,后将本息再存3年期p2:=%f\n", p2); printf("先存3年期,后将本息再存2年期p3:=%f\n", p3); printf("存1年期5次p4:=%f\n", p4); printf("存活期p5:=%f\n", p5); return 0; }
3.
#include <stdio.h> #include <math.h> int main() { float d = 300000, p = 6000, r = 0.01, m; m = log10(p / (p - d * r)) / log10(1 + r); printf("m=%6.2f\n", m);//m= 69.66 return 0; }
4.(1)
#include <stdio.h>int main() { char c1, c2; c1 = 97; c2 = 98; printf("c1=%c,c2=%c\n", c1, c2);// c1 = a, c2 = b printf("c1=%d,c2=%d\n", c1, c2);//c1 = 97,c2 = 98 return 0; }
(2)
#include <stdio.h>int main() { char c1, c2; c1 = 197; c2 = 198; printf("c1=%c,c2=%c\n", c1, c2); //c1 = ? c2 = ?(0~127,有意义,其他是乱码) printf("c1=%d,c2=%d\n", c1, c2);//c1=-59,c2=-58 return 0; }
(3)
#include <stdio.h>int main() { int c1, c2; c1 = 97; c2 = 98; printf("c1=%c,c2=%c\n", c1, c2); //c1 =a c2 =b printf("c1=%d,c2=%d\n", c1, c2);//c1=97,c2=98 return 0; }
#include <stdio.h>int main() { int c1, c2; c1 = 197; c2 = 198; printf("c1=%c,c2=%c\n", c1, c2); //c1 =? c2 =? printf("c1=%d,c2=%d\n", c1, c2);//c1=197,c2=198 return 0; }
5.
#include <stdio.h> int main() { int a, b; float x, y; char c1, c2; scanf_s("%d%d", &a, &b); scanf_s("%f %e", &x, &y); scanf_s("%c %c", &c1, &c2); printf("a=%d,b=%d,x=%f,y=%f,c1=%c,c2=%c\n", a, b, x, y, c1, c2); return 0; }
6.
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> int main() { char c1 = 0; char c2 = 0; char c3 = 0; char c4 = 0; char c5 = 0; scanf("%c %c %c %c %c", &c1, &c2, &c3, &c4, &c5); c1 = c1 + 4; c2 = c2 + 4; c3 = c3 + 4; c4 = c4 + 4; c5 = c5 + 4; printf("%c%c%c%c%c\n", c1, c2, c3, c4, c5); return 0; }
7.
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> int main() { float h, r, l, s, sq, vq, vz; float pi = 3.141526; printf("请输入圆半径r,圆柱高h∶"); scanf("%f,%f", &r, &h); l = 2 * pi * r; s = r * r * pi; sq = 4 * pi * r * r; vq = 3.0 / 4.0 * pi * r * r * r; vz = pi * r * r * h; printf("圆周长为: l=%6.2f\n", l); printf("圆面积为: s=%6.2f\n", s); printf("圆球表面积为: sq=%6.2f\n", sq); printf("圆球体积为: v=%6.2f\n", vq); printf("圆柱体积为: vz=%6.2f\n", vz); return 0; }
8.
(1)
#include <stdio.h> int main() { int c1, c2; //char c1, c2; printf("请输入两个字符c1,c2:"); c1 = getchar(); c2 = getchar(); printf("用putchar语句输出结果为:\n"); putchar(c1);//a putchar(c2);//b printf("\n"); printf("用printf语句输出结果为:\n"); printf("%c,%c\n", c1, c2);//a,b return 0; }
(2)
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> int main() { int c1, c2; printf("请输入两个整数c1,c2:"); scanf("%d,%d", &c1, &c2); printf("按字符输出结果:\n"); printf("%c,%c\n", c1, c2); printf("按ASCII码输出结果为:\n"); printf("%d,%d\n", c1, c2); return 0; }

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