PTA第二题

#include<string.h>
#include<stdio.h>
#include<malloc.h>

char n[120];
char a[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
char *p[10];
int main()
{
    scanf("%s",n);               //大数转换成字符串处理
    int len=strlen(n), sum=0;

    for(int i=0;i<len;i++)
        sum+=((int)n[i]-48);

    int j,k=0;
    if(sum==0){
        printf("ling");
        return 0;
    }

    while(sum!=0){
        j=sum%10;
        for(int i=0;i<10;i++){
            if(j==i){
                 p[k++]=a[i];
                 break;
            }
        }
        sum=sum/10;
    }

    for(int i=k-1;i>0;i--)
        printf("%s ",p[i]);

    printf("%s",p[0]);

    return 0;
}