LeetCode 2 Add Two Numbers
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
# Definition for singly-linked list.
# class ListNode
# attr_accessor :val, :next
# def initialize(val)
# @val = val
# @next = nil
# end
# end
# @param {ListNode} l1
# @param {ListNode} l2
# @return {ListNode}
def add_two_numbers(l1, l2)
return l1 if l2.nil?
return l2 if l1.nil?
s1 = Array.new
s2 = Array.new
n = Array.new
while l1
s1.unshift(l1.val)
l1 = l1.next
end
while l2
s2.unshift(l2.val)
l2 = l2.next
end
x = s1.join.to_i+s2.join.to_i
n = x.to_s.chars.map(&:to_i)
ans = ListNode.new(0)
d = ans
l = n.length()
l.times do
d.next = ListNode.new(n.pop)
d = d.next
end
ans.next
end
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