第六周作业
1.定义长度位5的整型数组,输入他们的值,用冒泡排序后输出.
public class work { public static void main(String[] args) { int[] arr={1,5,2,7,6}; for(int i=0;i<arr.length-1;i++){ for(int j=0;j<arr.length-1-i;j++){ if(arr[j]>arr[j+1]){ int temp=arr[j]; arr[j]=arr[j+1]; arr[j+1]=temp; } } } for(int i=0;i<arr.length;i++){ System.out.print(arr[i]+""); } } }
2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"
import java.util.*; public class work { public static void main(String[] args) { Scanner a = new Scanner(System.in); int[] b = { 34, 22, 35, 67, 45, 66, 12, 33 }; int k = -1; System.out.println("输入一个数"); int c = a.nextInt(); for (int i = 0; i < b.length; i++) { if (b[i] == c) { k = i; System.out.println("下标为" + i); break; } } if (k == -1) { System.out.println("not found"); } } }
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。
public class work { public static void main(String[] args) { double[][] a = {{1.1,2.2,3.3,4.4},{5.5,6.6,7.7,8.8},{10.1,10.2,10.3,10.4},{11.1,11.2,11.3,11.4},{12.1,12.2,12.3,12.4}}; for(int i = 0;i < 5;i++) { for(int j = 0;j < 4;j++) { System.out.print(a[i][j]+" "); } System.out.println(); } } }
4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.
public class work { public static void main(String[] args) { int arr[][] = { {1,2,3}, { 5,6,8}, {11,15,17}, {16,19,21} }; int max = arr[0][0]; for (int i = 0; i < arr.length; i++) { for (int j = 0; j < arr[i].length; j++) { if (arr[i][j] > max) { max = arr[i][j]; } } } System.out.println("该二维数组的最大值为:"+max); } }