【Leetcode】Binary Tree Level Order Traversal

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).

For example:
Given binary tree {3,9,20,#,#,15,7},

    3
   / \
  9  20
    /  \
   15   7

return its level order traversal as:

[
  [3],
  [9,20],
  [15,7]
]

思路：使用一个队列进行存储，同一时候利用两个变量来记录该层的节点个数，以及下一层的节点个数。

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<vector<int> > levelOrder(TreeNode *root) {
        vector<vector<int>> result;
        
        if(root == NULL)    return result;
        
        queue<TreeNode *> lq;
        lq.push(root);
        int curlc = 1;
        int nextlc = 0;
        
        while(!lq.empty())
        {
            vector<int> level;
            while(curlc > 0)
            {
                TreeNode * temp = lq.front();
                lq.pop();
                curlc--;
                level.push_back(temp->val);
                
                if(temp->left)
                {
                    lq.push(temp->left);
                    nextlc++;
                }
                if(temp->right)
                {
                    lq.push(temp->right);
                    nextlc++;
                }
            }
            
            curlc = nextlc;
            nextlc = 0;
            result.push_back(level);
        }
        
        return result;
    }
};