hello world!
$\displaystyle\sum_{n=1}^{\infty}\frac{1}{n^2}=\frac{\pi^2}{6}$,
$\left\{
\begin{array}{l}
x+y=1\\
x-y=2\\
\end{array}
\right.$
$\displaystyle\sum_{n=1}^{\infty}\frac{1}{n^2}=\frac{\pi^2}{6}$,
$\left\{
\begin{array}{l}
x+y=1\\
x-y=2\\
\end{array}
\right.$