iOS 如何在整个屏幕中都能实现滑动返回的效果
1 - (void)setupGetsInNav 2 { 3 UIGestureRecognizer *gesture = self.interactivePopGestureRecognizer; 4 gesture.enabled = NO; 5 UIView *gestureView = gesture.view; 6 7 UIPanGestureRecognizer *popRecognizer = [[UIPanGestureRecognizer alloc] init]; 8 popRecognizer.delegate = self; 9 popRecognizer.maximumNumberOfTouches = 1; 10 [gestureView addGestureRecognizer:popRecognizer]; 11 /** 12 * 获取系统手势的target数组 13 */ 14 NSMutableArray *_targets = [gesture valueForKey:@"_targets"]; 15 /** 16 * 获取它的唯一对象，我们知道它是一个叫UIGestureRecognizerTarget的私有类，它有一个属性叫_target 17 */ 18 id gestureRecognizerTarget = [_targets firstObject]; 19 /** 20 * 获取_target:_UINavigationInteractiveTransition，它有一个方法叫handleNavigationTransition: 21 */ 22 id navigationInteractiveTransition = [gestureRecognizerTarget valueForKey:@"_target"]; 23 /** 24 * 通过前面的打印，我们从控制台获取出来它的方法签名。 25 */ 26 SEL handleTransition = NSSelectorFromString(@"handleNavigationTransition:"); 27 /** 28 * 创建一个与系统一模一样的手势，我们只把它的类改为UIPanGestureRecognizer 29 */ 30 [popRecognizer addTarget:navigationInteractiveTransition action:handleTransition]; 31 32 }
1 - (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer { 2 /** 3 * 这里有两个条件不允许手势执行，1、当前控制器为根控制器；2、如果这个push、pop动画正在执行（私有属性） 4 */ 5 return self.viewControllers.count != 1 && ![[self valueForKey:@"_isTransitioning"] boolValue]; 6 }
只需要在全局的导航控制器中添加上边代码即可
