实验课作业2
实验任务-1
源代码
#include<stdio.h> #include<stdlib.h> #include<time.h> #define N 5 int main() { int number; int i; srand(time(0)); for (i = 0; i < N; ++i) { number = rand() % 500 + 1; printf("20228329%04d\n", number); } return 0; }
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问题answer
1,赋给number一个1-500的随机数
2,打印输出一个随机学号
实验任务-2
源代码
#include<stdio.h> #include<stdlib.h> #include<time.h> int main() { int i, n; srand(time(0)); int a = rand() % 30 + 1; printf("猜猜2022年11月哪一天会是你的lucky day\n"); printf("开始喽,你有三次机会,猜吧(1~30):\n"); for (i = 1; i <= 3; ++i) { scanf_s("%2d", &n); if (n == a) { printf("哇,你猜对了:)"); break; } else if (n < a) { printf("你猜的日期早了,你的lucky day还没到呢\n"); if (i >= 3) { break; } printf("再猜:\n"); } else if (n > a) { printf("你猜的日期晚了,你的lucky day已经过了\n"); if (i >= 3) { break; } printf("再猜:\n"); } } printf("次数用完了,偷偷告诉你;11月,你的lucky day是%d",a); return 0; }
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实验任务-3
源代码
#include<stdio.h> #include<stdlib.h> int main() { char trafficlight; while (trafficlight=getchar(),getchar() != EOF) { switch (trafficlight) { case 'r':printf("stop!\n"); break; case 'g':printf("go go go\n"); break; case 'y':printf("wait a minute\n"); break; default:printf("something must be wrong...\n"); break; } } return 0; }
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实验任务-4
源代码
#include<stdio.h> #include<stdlib.h> int main() { char trafficlight; while (trafficlight=getchar(),getchar() != EOF) { switch (trafficlight) { case 'r':printf("stop!\n"); break; case 'g':printf("go go go\n"); break; case 'y':printf("wait a minute\n"); break; default:printf("something must be wrong...\n"); break; } } return 0; }
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实验任务-5
源代码
#include<stdio.h> #include<stdlib.h> int main() { int line, colum; for (line = 1; line <= 9; ++line) { for (colum = 1; colum <= line; ++colum) { printf("%dx%d=%2d ", line, colum, line * colum); } printf("\n"); } return 0; }
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实验任务-6
源代码
#include<stdio.h> #include<stdlib.h> int main() { int a, b, c, n; scanf_s("%d", &n); printf("input n:%d\n", n); for (a = 1; a <= n; ++a) { for (b = 1; b <= 5 * (a - 1); ++b) { printf(" "); } for (c = 1; c <= 2 * n - 2 * a + 1; ++c) { printf(" o "); } printf("\n"); for (b = 1; b <= 5 * (a - 1); ++b) { printf(" "); } for (c = 1; c <= 2 * n - 2 * a + 1; ++c) { printf("<H> "); } printf("\n"); for (b = 1; b <= 5 * (a - 1); ++b) { printf(" "); } for (c = 1; c<= 2*n-2*a+1; ++c) { printf("I I "); } printf("\n"); } return 0; }
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1. 需打印2*n-2*i+1个小人
2. 需打印5*(i-1)个空格


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