获取数组中时间的最小值

let arr = ["2022-01-11 12:00:00", "2022-06-14 12:00:00", "2022-05-14 13:00:00", "2022-04-24 11:00:00", "2022-06-14 16:00:00", "2022-05-14 15:00:00", "2022-02-14 15:00:00", "2022-03-14 11:00:00", "2022-04-14 15:00:00", "2022-01-14 11:00:00", "2022-03-14 12:00:00"]

//方法1：
let minValue = arr.reduce(function(total,item){
    if(total == ''){return item}
    let time = new Date(item).getTime()
    if(time < new Date(total).getTime()){
        return item;
    }else{
        return total
    }
},'');
console.log('>',minValue)

//方法2 - 简化方法1
console.log('>>',arr.reduce((time1,time2)=> new Date(time1)>new Date(time2)?time2:time1,arr[0]))