根据名称获取经纬度 

 1  public static string[] GetValue(Sheet_Excel model)
 2         {
 3             MessageModel result = new MessageModel();
 4             string[] arrys = new string[] { };
 5             try
 6             {
 7                 string ak = "BfH08PCAsZ8SfbiXXEXRkSzn4MA00Mdk";
 8                 // string ak = "r8fiyxWjDHfFP0AUztl4avxqsocvlXuZ";11                 var _city = model.City;
12                 var address = model.Address;
13                 //address = address.Replace("#", "");
14 
15                 var urlName = $"{address}";18 
19                 //pois 是否搜索周边 0或1
20                 //string Url = @"http://api.map.baidu.com/geocoding/v3/?address=" + urlName + "&output=json&ak=" + ak + "";
21                 string Url = $"http://api.map.baidu.com/geocoding/v3/?address={urlName}&output=json&ak={ak}";
22                 HttpWebRequest request = (HttpWebRequest)WebRequest.Create(Url);
23                 request.KeepAlive = false;
24                 request.Method = "GET";
25                 request.ContentType = "application/json";
26                 using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
27                 {
28                     using (Stream myResponseStream = response.GetResponseStream())
29                     {
30                         // StreamReader myStreamReader = new StreamReader(myResponseStream, Encoding.GetEncoding("utf-8"));
31                         using (StreamReader myStreamReader = new StreamReader(myResponseStream))
32                         {
33                             string responseString = myStreamReader.ReadToEnd();
34                             var jo = JsonConvert.DeserializeObject<JObject>(responseString);
35                             string lat = "", lng = "";
36                             if (string.Equals(jo["status"].ToString(), "0") && jo["result"].ToString() != "[]")
37                             {
38                                 lat = jo["result"]["location"]["lat"].ToString();
39                                 lng = jo["result"]["location"]["lng"].ToString();
40                             }
41 
42                             arrys = new string[] { lng, lat };
43                         }
44                     }
45                 }
46                 result.response = arrys;
47             }
48             catch (Exception ex) { result.msg = ex.ToString(); }
49 
50             Thread.Sleep(200);
51 
52             return arrys;
53         }

 

posted @ 2021-06-03 12:10  Ly博客  阅读(346)  评论(0)    收藏  举报