随笔分类 - 凸包
摘要:struct point{ int x,y;} p[N],stack[N];bool cmp(point A,point B){ if(A.y==B.y)return A.x1&&cross(stack[top-2],stack[top-1],p[i])=0; i--) { ...
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摘要:Shape of HDUTime Limit: 3000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5134Accepted Submission(s): 2334Proble...
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摘要:Diamond DealerTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 606Accepted Submission(s): 175Proble...
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摘要:最大三角形Time Limit: 5000/2000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3184Accepted Submission(s): 1075Problem Descr...
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摘要:Surround the TreesTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7356Accepted Submission(s): 2813...
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摘要:WallTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3257Accepted Submission(s): 931Problem Descrip...
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摘要:struct point{ double x,y,angel;} p[N],stack[N];int top,n;double dis(point a,point b)//求距离{ return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));...
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摘要:先理解下凸包说凸包首先要说凸性的定义,简单点说就是平面邻域中任意两点所在的线段上的点都在该邻域中,则该邻域具有凸性。简单推敲一下,就可以发现如果邻域中存在一阶导数不连续的点一定无法被某点集线性表示出来。再往下的内容属于数学分析了,对我们的算法设计帮助不大,暂时先不管。一般的计算几何问题都是处理的离散...
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