【python----定义函数】

# 创建函数
def info():
    # age = 18
    # name = 'lxc'
    # print(age,name)
    print('我是李轩臣')
    print('我21')
info()         #  调用函数   执行一次
#  我是李轩臣
#   我21

# 定义函数求和
def he():
    a=5
    b=3
    print(a+b)
he()




def mdmP():
    print('马什么梅?')
    input('')
    print('马东什么?')
    input('')
    print('o,马冬梅!')

mdmP()


def info():
    print('*'*20)
    return 6,7
    print('------------')
    return 5,6
info()

#  定义函数 查找元素是否在列表里 在 返回 位置 不在 返回 -1
#   两种方法
l = [1,2,3,6,5,8,9]
def info():
    '''

    :return: index --------  -1
    '''
    for i in l :
        i = 5
        if i in l:
            return l.index(i)
        else:
            return -1
li = info()
print(li)

def findl():
    l = [78,64,2,87,5]
    for i in range(len(l)):
        if l[i] == 2:
            return i
        else:
            return -1
findl()

#  取最大值
def max_value():
    l = [99,66,741,9898]
    max_n = l[0]
    for i in range(len(l)):
        if l[i] > max_n:
            max_n = l[i]
    return max_n
re = max_value()
print(re)


a = 5
b= 6
c=1
def max_l():
    re = (a if a>b else b) if (a if a>b else b)>c else c
    rt = (a if a<b else b) if (a if a<b else b)<c else c
    return re,rt
li = max_l()
print(li)

# 9* 9
def nine_nine():
    for i in range(1,10):
        for j in range(1,i+1):
            print(f'{i}*{j}={i*j}',end='\t')

        print()
nine_nine()



# re = [f'{i}*{j}={i*j}']

#  计算 字符长度
def info():
    s= "hello word "
    total =0
    for i in s:
        total = total+1
    print(total)

info()

 # 返回多个值
def rey_demo():
    return 1,2,3,6,58,6
a,b,c,d,e_,f = rey_demo()    #  拆包
re = rey_demo()
print(re)
print(e_)
a,_,_,_,_,f = rey_demo()
a,*_=rey_demo()
print(*_)

#  函数的参数
#   封闭原则
def paramater(s):
    toatal = 0
    for i in s:
        toatal = toatal+1
    return toatal

print(paramater('helloword'))

def info(name):
    print(f"wojiaolixuanche{name}")
info('李先生')


def j(row,colime):    #  形参
    for i in range(row):
        for j in range(1,colime):
            print(f"*",end=" ")
        print()
j(9,9)                #  实参

def isexist(l,num):
    for i in range(len(l)):
        if l[i] == num:
            return i
    return -1
re = isexist([1,2,3,6,51,49,2,3,23,],3)  #  传值
print(re)

 

posted @ 2020-07-22 17:07  XuanchenLi  阅读(148)  评论(0编辑  收藏  举报