python题目

打印0-1+2-3+4。。。99的值

i = 0
j = 1
sum = 0
s = '0'
while i < 100:
    i += 1
    j = -j
    sum = sum + i*jz
    s = s + '+' + str(i*j)
print('%s %s' % (s,sum))

升级版，遇到88跳过
i = 0
j = 1
sum = 0
s = '0'
while i < 99:
    i = i +1if i == 88:
        continue
    else:
        x = i*j
        sum = sum + x
        s = s + '+' + str(x)
　　　　　j = -j

print ('%s %s' %(s,sum))