数组_leetcode27

# 解题思路： 无  20190302 找工作期间


class Solution(object):
    def removeElement(self, nums, val):
        """
        :type nums: List[int]
        :type val: int
        :rtype: int

        """

        k = 0

        for i in range(len(nums)):
            if nums[i] != val:
                nums[k] = nums[i]
                k += 1

        return k


nums = [0,1,2,2,3,0,4,2]
nums2 = [3,2,2,3]

s = Solution()
print s.removeElement(nums2,3)