数据结构之二叉树 

  1 #include<iostream>
  2 #include<stack>
  3 #include<queue>
  4 using namespace std;
  5 typedef struct tnode TN;
  6 typedef struct tnode* TT;
  7 struct tnode{
  8     int data;
  9     TT left,right;
 10 };
 11 void  creatree(TT &k)            //前序遍历建立二叉树
 12 {
 13     int data1;
 14     printf("请输入该分支的头节点：");
 15     cin >> data1;
 16     if (data1 ==-1)
 17         k = NULL;
 18     else{
 19         k = (TT)malloc(sizeof(TN));
 20         k->data = data1;
 21         creatree(k->left);
 22         creatree(k->right);
 23     }
 24 }
 25 void preorder(TT root)          //前序遍历
 26 {
 27     if (root){
 28         printf("%d ", root->data);
 29         preorder(root->left);
 30         preorder(root->right);
 31     }
 32 }
 33 ////////////四种非递归遍历方法
 34 
 35 void preorder2(TT root)                        //前序遍历
 36 {
 37     stack<TT> sk;
 38     TT wk = root;
 39     while (wk || !sk.empty())
 40     {
 41         while (wk)                         //直到左子树为空的时候
 42         {
 43             sk.push(wk);
 44             cout << wk->data << " ";
 45             wk = wk->left;                
 46         }
 47         if (!sk.empty())
 48         wk= sk.top()->right; sk.pop();        //为空时栈顶为最短父节点，遍历该父节点的右子树
 49     }
 50 }
 51 void midorder(TT root)                            //中序遍历
 52 {
 53     TT wk = root;
 54     stack<TT> sk;
 55     while (wk||!sk.empty())
 56     {
 57         while (wk)
 58         {
 59             sk.push(wk);
 60             wk = wk->left;
 61         }
 62         if (!sk.empty())
 63         {
 64             wk = sk.top(); sk.pop();
 65             cout << wk->data<<" ";
 66             wk = wk->right;
 67         }
 68     }
 69 }
 70 void postorder(TT root)                //后序遍历
 71 {
 72     stack<TT> sk;
 73     TT wk = root;                         //工作指针
 74     TT r = NULL;                        //标志指针
 75     while (wk || !sk.empty())
 76     {
 77         if (wk){                         //wk非空
 78             sk.push(wk);
 79             wk = wk->left;
 80         }
 81         else
 82         {
 83             wk = sk.top();
 84             if (wk->right&&wk->right != r)      //右子树存在且没有被访问过
 85             {
 86                 wk = wk->right;
 87             }
 88             else
 89             {
 90                 cout << wk->data << " ";
 91                 sk.pop();
 92                 r = wk;                              //表示该节点已经访问
 93                 wk = NULL;                           //下一步要么结束要么wk等于栈顶元素继续访问左子树或者右子树---所以令其为空
 94             }
 95         }
 96     }
 97 }
 98 ////
 99 void levelorder(TT root)                                //层次遍历
100 {
101     queue<TT> sk;                                   //由层次遍历的特点：左子树先访问，而且左子树的孩子也先访问
102     TT wk = root;
103     sk.push(wk);
104     while (!sk.empty())
105     {
106         wk = sk.front();
107         cout <<wk->data << " ";
108         if (wk->left != NULL)sk.push(wk->left);
109         if (wk->right != NULL)sk.push(wk->right);
110         sk.pop();
111     }
112 }
113 int main()
114 {
115     TT st=NULL;
116     cout << "前序遍历建立二叉树："<<endl;
117     creatree(st);
118     cout << "前序遍历1：" << endl;
119     preorder(st);
120     cout << endl;
121     cout << "前序遍历2：" << endl;
122     preorder2(st);
123     cout << endl;
124     cout << "中序遍历：" << endl;
125     midorder(st);
126     cout << endl;
127     cout << "后序遍历：" << endl;
128     postorder(st);
129     cout << endl;
130     cout << "层次遍历：" << endl;
131     levelorder(st);
132     return 0;
133 }

 

posted @ 2018-08-16 16:07  代码拯救世界可以吗  阅读(231)  评论(0)    收藏  举报