mysql 数据占用资源

SELECT TABLE_NAME,DATA_LENGTH+INDEX_LENGTH,TABLE_ROWS FROM TABLES WHERE TABLE_SCHEMA='xx' AND TABLE_NAME='xxx'


SELECT
a.table_schema ,
a.table_name ,
concat(round(sum(DATA_LENGTH / 1024 / 1024) + sum(INDEX_LENGTH / 1024 / 1024) ,2) ,'MB') total_size ,
concat(round(sum(DATA_LENGTH / 1024 / 1024) , 2) ,'MB') AS data_size ,
concat(round(sum(INDEX_LENGTH / 1024 / 1024) , 2) ,'MB') AS index_size
FROM
information_schema. TABLES a
WHERE
a.table_schema = 'xxx'
AND a.table_name = 'xxx';

 

posted @ 2022-07-13 14:47  不再犯错  阅读(95)  评论(0)    收藏  举报