with rank as(
SELECT group_id,SUM(pay_dollar) as pay_dollars,count(*) as count FROM
(select mod(player_id,33) as group_id, pay_amount*exchange as pay_dollar FROM mafia1.offer_purchase
WHERE timestamp >='2019-10-21 12:10:00' and timestamp <='2019-10-22 18:50:00' and player_id not in(select player_id FROM mafia1.create_player where uid in(select uid from mafia1.internal_user)))
# and player_id in(select player_id FROM mafia1.create_player where timestamp >='2019-07-01'))
#where pay_dollar >=90
group by group_id
order by pay_dollars)
select group_id, pay_dollars/total_dollars as ratio, count, pay_dollars, pay_dollars/count as mean FROM rank,(select SUM(pay_dollars) as total_dollars FROM rank)
Order by pay_dollars
with rank as(
SELECT group_id, SUM(pay_dollar) as pay_dollars, count(*) as count FROM
(select mod(player_id, 33) as group_id, pay_amount*exchange as pay_dollar FROM mafia1.offer_purchase
WHERE timestamp >='2019-10-23 13:15:00' and timestamp <='2019-10-23 23:50:00' and player_id not in (select player_id FROM mafia1.create_player where uid in (select uid from mafia1.internal_user)))
# and player_id in (select player_id FROM mafia1.create_player where timestamp >='2019-07-01'))
#where pay_dollar >=90
group by group_id
order by pay_dollars)
select group_id, pay_dollars/total_dollars as ratio, count, pay_dollars, pay_dollars/count as mean FROM rank, (select SUM(pay_dollars) as total_dollars FROM rank)
Order by pay_dollars
with rank as(
SELECT group_id, SUM(pay_dollar) as pay_dollars, count(*) as count FROM
(select mod(player_id, 33) as group_id, pay_amount*exchange as pay_dollar FROM mafia1.offer_purchase
WHERE timestamp >='2019-10-19 03:00:00' and timestamp <='2019-10-23 23:50:00' and player_id not in (select player_id FROM mafia1.create_player where uid in (select uid from mafia1.internal_user)))
# and player_id in (select player_id FROM mafia1.create_player where timestamp >='2019-07-01'))
#where pay_dollar >=90
group by group_id
order by pay_dollars)
select group_id, pay_dollars/total_dollars as ratio, count, pay_dollars, pay_dollars/count as mean FROM rank, (select SUM(pay_dollars) as total_dollars FROM rank)
Order by pay_dollars