sql 精读(四) 标准 SQL 中聚合分析功能示例

求和

WITH Produce AS
 (SELECT 'kale' as item, 23 as purchases, 'vegetable' as category
  UNION ALL SELECT 'orange', 2, 'fruit'
  UNION ALL SELECT 'cabbage', 9, 'vegetable'
  UNION ALL SELECT 'apple', 8, 'fruit'
  UNION ALL SELECT 'leek', 2, 'vegetable'
  UNION ALL SELECT 'lettuce', 10, 'vegetable') 
 
SELECT item, purchases, category, SUM(purchases)
  OVER () AS total_purchases
FROM Produce;
  

+-------------------------------------------------------+
| item      | purchases  | category   | total_purchases |
+-------------------------------------------------------+
| orange    | 2          | fruit      | 54              |
| leek      | 2          | vegetable  | 54              |
| apple     | 8          | fruit      | 54              |
| cabbage   | 9          | vegetable  | 54              |
| lettuce   | 10         | vegetable  | 54              |
| kale      | 23         | vegetable  | 54              |
+-------------------------------------------------------+

小计

WITH Produce AS
 (SELECT 'kale' as item, 23 as purchases, 'vegetable' as category
  UNION ALL SELECT 'orange', 2, 'fruit'
  UNION ALL SELECT 'cabbage', 9, 'vegetable'
  UNION ALL SELECT 'apple', 8, 'fruit'
  UNION ALL SELECT 'leek', 2, 'vegetable'
  UNION ALL SELECT 'lettuce', 10, 'vegetable') 
 
SELECT item, purchases, category, SUM(purchases)
  OVER (
    PARTITION BY category
    ORDER BY purchases
    ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING
  ) AS total_purchases
FROM Produce

+-------------------------------------------------------+
| item      | purchases  | category   | total_purchases |
+-------------------------------------------------------+
| orange    | 2          | fruit      | 10              |
| apple     | 8          | fruit      | 10              |
| leek      | 2          | vegetable  | 44              |
| cabbage   | 9          | vegetable  | 44              |
| lettuce   | 10         | vegetable  | 44              |
| kale      | 23         | vegetable  | 44              |
+-------------------------------------------------------+

累计求和

WITH Produce AS
 (SELECT 'kale' as item, 23 as purchases, 'vegetable' as category
  UNION ALL SELECT 'orange', 2, 'fruit'
  UNION ALL SELECT 'cabbage', 9, 'vegetable'
  UNION ALL SELECT 'apple', 8, 'fruit'
  UNION ALL SELECT 'leek', 2, 'vegetable'
  UNION ALL SELECT 'lettuce', 10, 'vegetable') 

  

SELECT item, purchases, category, SUM(purchases)
  OVER (
    PARTITION BY category
    ORDER BY purchases
    ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
    --ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING
    
  ) AS total_purchases
FROM Produce

+-------------------------------------------------------+
| item      | purchases  | category   | total_purchases |
+-------------------------------------------------------+
| orange    | 2          | fruit      | 2               |
| apple     | 8          | fruit      | 10              |
| leek      | 2          | vegetable  | 2               |
| cabbage   | 9          | vegetable  | 11              |
| lettuce   | 10         | vegetable  | 21              |
| kale      | 23         | vegetable  | 44              |
+-------------------------------------------------------+