sql array 数组基本用法(四)

查询嵌套数组

  SELECT "800M" AS race,
    [STRUCT("Rudisha" as name, [23.4, 26.3, 26.4, 26.1] as splits),
     STRUCT("Makhloufi" as name, [24.5, 25.4, 26.6, 26.1] as splits),
     STRUCT("Murphy" as name, [23.9, 26.0, 27.0, 26.0] as splits),
     STRUCT("Bosse" as name, [23.6, 26.2, 26.5, 27.1] as splits),
     STRUCT("Rotich" as name, [24.7, 25.6, 26.9, 26.4] as splits),
     STRUCT("Lewandowski" as name, [25.0, 25.7, 26.3, 27.2] as splits),
     STRUCT("Kipketer" as name, [23.2, 26.1, 27.3, 29.4] as splits),
     STRUCT("Berian" as name, [23.7, 26.1, 27.0, 29.3] as splits)]
       AS participants

这是一行数据，查询的时候需要把数据展开

WITH races AS (
  SELECT "800M" AS race,
    [STRUCT("Rudisha" as name, [23.4, 26.3, 26.4, 26.1] as splits),
     STRUCT("Makhloufi" as name, [24.5, 25.4, 26.6, 26.1] as splits),
     STRUCT("Murphy" as name, [23.9, 26.0, 27.0, 26.0] as splits),
     STRUCT("Bosse" as name, [23.6, 26.2, 26.5, 27.1] as splits),
     STRUCT("Rotich" as name, [24.7, 25.6, 26.9, 26.4] as splits),
     STRUCT("Lewandowski" as name, [25.0, 25.7, 26.3, 27.2] as splits),
     STRUCT("Kipketer" as name, [23.2, 26.1, 27.3, 29.4] as splits),
     STRUCT("Berian" as name, [23.7, 26.1, 27.0, 29.3] as splits)]
       AS participants)
SELECT
  race,
  participant
FROM races r
CROSS JOIN UNNEST(r.participants) as participant;

race	participant
800M	{Rudisha, [23.4, 26.3, 26.4, 26.1]}
800M	{Makhloufi, [24.5, 25.4, 26.6, 26.1]}
800M	{Murphy, [23.9, 26, 27, 26]}
800M	{Bosse, [23.6, 26.2, 26.5, 27.1]}
800M	{Rotich, [24.7, 25.6, 26.9, 26.4]}
800M	{Lewandowski, [25, 25.7, 26.3, 27.2]}
800M	{Kipketer, [23.2, 26.1, 27.3, 29.4]}
800M	{Berian, [23.7, 26.1, 27, 29.3]}