python super 变参数问题（五）

这是Python多层继承的一个特例，祖父，父亲，儿子都有 draw 方法，那么经过多次继承后，

• 如何对于不同层次的方法传递参数呢，可以看这篇文章python super 理解（四）
• 如何对于不同层次的方法传递参数呢，那么这个例子展现了一种解法，但是这种做法不够通用，在下一篇文章我给出更加通用的玩法

def myFun(ff,**kwargs): 
    
    # print(kwargs)
    for key, value in kwargs.items():
        print ("%s == %s" %(key, value))
    print('#'*12)
 
# Driver code
myFun(ff ='a',first ='Geeks', mid ='for', last='Geeks')    

# input_dict={'first' :'Geeks', 'mid' :'for', 'last':'Geeks'}
# myFun(**input_dict)

first == Geeks
mid == for
last == Geeks
############

class Root:
    def draw(self):
        # the delegation chain stops here
        
        print('Root Drawing draw ')
        assert not hasattr(super(), 'draw')

class Shape(Root):
    def __init__(self, shapename, **kwds):
        self.shapename = shapename
        # print('Shape class',kwds)
        super().__init__(**kwds)
    def draw(self):
        print('Shape Drawing.  Setting shape to:', self.shapename)
        super().draw()

class ColoredShape(Shape):
    def __init__(self, color, **kwds):
        self.color = color
        
        # print('ColoredShape class',kwds)
        super().__init__(**kwds)
    def draw(self):
        print('ColoredShape Drawing.  Setting color to:', self.color)
        super().draw()

cs = ColoredShape(color='blue', shapename='square')
cs.draw()

ColoredShape Drawing.  Setting color to: blue
Shape Drawing.  Setting shape to: square
Root Drawing draw