ajax中的几种方法$.get,$.post,$.getJSON

    public void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.getWriter().write("{\"name\":\"zhangsan\",\" age\":18}");
    }

$.get

 	$(function(){
  		$.get("/719js/BServlet",{"name":"234"},function(data){
  			alert(data);
  		var s=eval("("+data+")");
  		alert(s.name+"---"+s.age);
  		});
  		
  	});

$.getJSON

  	$(function(){
  		$.getJSON("/719js/BServlet",{"name":"234"},function(data){
				alert(data.name);
  		});
  		
  	});

//为什么用不了 post因为 我压根就没写doPost
$(function(){
$.get("/719js/BServlet",{"name":"234"},function(data){
alert(data.name);
},"json");

});

  

posted on 2017-07-19 20:53  lkjhgfdsa123  阅读(98)  评论(0编辑  收藏  举报