C语言实验3
实验任务3-1
#include<stdio.h> #include<stdlib.h> #include<time.h> #include<windows.h> #define N 80 void print_text(int line,int col,char text[]); void print_spaces(int n); void print_black_lines(int n); int main(){ int line,col,i; char text[N] = "hi,April~"; srand(time(0)); for(i = 1;i <= 10;++i){ line = rand() % 25; col = rand() % 80; print_text(line,col,text); Sleep(1000); } return 0; } void print_spaces(int n){ int i; for(i=1;i <= n;++i) printf(" "); } void print_black_lines(int n){ int i; for(i=1;i <= n;++i) printf("\n"); } void print_text(int line,int col,char text[]){ print_black_lines(line-1); print_spaces(col-1); printf("%s",text); }

实验任务3-2-1
#include <stdio.h> long long fac(int n); int main() { int i, n; printf("Enter n: "); scanf("%d", &n); for (i = 1; i <= n; ++i) printf("%d! = %lld\n", i, fac(i)); return 0; } long long fac(int n) { static long long p = 1; p = p * n; return p; }

实验任务3-2-2
// 练习:局部static变量特性 #include <stdio.h> int func(int, int); // 函数声明 int main() { int k = 4, m = 1, p1, p2; p1 = func(k, m); // 函数调用 p2 = func(k, m); // 函数调用 printf("%d, %d\n", p1, p2); return 0; } // 函数定义 int func(int a, int b) { static int m = 0, i = 2; i += m + 1; m = i + a + b; return m; }

当函数返回后,局部静态变量static的值不会被销毁,而是保留下来,在下次调用函数时,这个变量的值还是上一次离开时的值。这不同于普通的局部变量,它们会在函数返回后被销毁。
实验任务3
#include <stdio.h> long long func(int n); // 函数声明 int main() { int n; long long f; while (scanf("%d", &n) != EOF) { f = func(n); // 函数调用 printf("n = %d, f = %lld\n", n, f); } return 0; } // 函数定义 long long func(int n){ long long f; if(n==1) { f=1; } else { f=2*func(n-1)+1; } return f; }

实验任务3-4
#include <stdio.h> int func(int n, int m); int main() { int n, m; while(scanf("%d%d", &n, &m) != EOF) printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m)); return 0; } // 函数定义 int func(int n, int m){ int i; int up=1; int down=1; if(m>n) { return 0; } else if(m==0&&n==0) { return 1; } else { for(i=1;i<=m;i++) { up*=n-i+1; down*=i; } return up/down;

实验任务3-5
#include<stdio.h> #include<stdlib.h> #include<math.h> void hanoi(unsigned int n,char from,char temp,char to); void moves(unsigned int n,char from,char to); int main() { unsigned int n; int s; while(scanf("%d",&n)!=EOF) { hanoi(n,'A','B','C'); s=pow(2,n)-1; printf("一共移动了%d次\n",s); } system("pause"); return 0; } void hanoi(unsigned int n,char from,char temp,char to) { if(n==1) moves(n,from,to); else { hanoi(n-1,from,to,temp); moves(n,from,to); hanoi(n-1,temp,from,to); } } void moves(unsigned int n,char from,char to) { printf("%d:%c-->%c\n",n,from,to); }

实验任务3-6
#include <stdio.h> #include <math.h> long func(long s); // 函数声明 int main() { long s, t; printf("Enter a number: "); while (scanf("%ld", &s) != EOF) { t = func(s); // 函数调用 printf("new number is: %ld\n\n", t); printf("Enter a number: "); } return 0; } // 函数定义 // 待补足。。。 long func(long s){ long ans; long digit,t; ans=0; t=1; while(s!=0){ digit=s%10; if(digit%2){ ans +=t*digit; t*=10; } s /=10; } return ans; }

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