c# 开根号 牛顿迭代

 double n = 1,m;
               Console.WriteLine("请输入您要开根号的数:");
               m = Convert.ToDouble(Console.ReadLine());
               for (int i = 0; 1==1; i++)
               {
                   n = (n + m / n) /2;
                
                   if (i==10000)
                   {
                       break; 
                   }
               }
               Console.WriteLine(n);

posted @ 2015-03-06 16:03  冷先生  阅读(935)  评论(0编辑  收藏  举报