普通人学习rust——从零到放弃 变量、不可变量、常量

普通人学习rust——从零到放弃 变量、不可变量、常量

环境

本文章内容基于如下环境,如若出入请参考当前环境。

rustc 1.42.0 (b8cedc004 2020-03-09)
cargo 1.42.0 (86334295e 2020-01-31)

前言

可变变量、不可变量、常量 是rust语言的一个特性。本篇文章主要讲rust的三个关键字:letmutconst

不可变量

let 是创建变量的关键字,rust默认创建的变量为不可变量。吐槽:大多数情况下,程序都是使用可变变量,而rust却默认创建的不可变的变量,纯粹为了特别而特别吧!

//设置不可变量
    let x = 5;
	println!("let x={}",x);

不可变量不可对变量进行修改,错误示例

	//设置不可变量
    let x = 5;
	println!("let x={}",x);
	//不可以对不可变量进行修改
	x = 6;
	println!("let x={}",x);

编译错误

error[E0384]: cannot assign twice to immutable variable `x`
 --> main.rs:6:2
  |
3 |     let x = 5;
  |         -
  |         |
  |         first assignment to `x`
  |         help: make this binding mutable: `mut x`
...
6 |     x = 6;
  |     ^^^^^ cannot assign twice to immutable variable

error: aborting due to previous error

For more information about this error, try `rustc --explain E0384`.

不可变量可以重新定义,重新定义包括改变类型

正确示例

	//设置不可变量
    let x = 5;
	println!("let x={}",x);
	//重新定义
	let x = 6;
	println!("let x={}",x);
	//重新定义,并改变类型
	let x = "字符串";
	println!("let x={}",x);

运行结果

let x=5
let x=6
let x=字符串

可变变量

绝大多数情况下,程序都是定义为可以修改的变量,变量本来就是要变的,只是rust加了一层不可变而已。rust下需要加上mut才能使变量可以修改。

正确示例

	//设置可变量
    let mut x = 5;
	println!("let x={}",x);
	//修改值
	x = 6;
	println!("let x={}",x);

运行结果

let x=5
let x=6

修改值需要保持类型一致,错误示例

	//设置不可变量
    let mut x = 5;
	println!("let x={}",x);
	//修改值
	x = "字符串";
	println!("let x={}",x);

编译错误

error[E0308]: mismatched types
 --> main.rs:6:6
  |
6 |     x = "字符串";
  |         ^^^^^^^^ expected integer, found `&str`

error: aborting due to previous error

For more information about this error, try `rustc --explain E0308`.

常量

定义常量使用const作为关键字。

	//设置常量
    const PI:f32 = 3.14;
	println!("const PI={}",PI);

运行结果

const PI=3.14

常量不可修改,这跟不可变量是一样的
常量不可重新定义,错误示例1

fn main(){
	//设置常量
    const PI:f32 = 3.14;
	println!("const PI={}",PI);
	const PI:f32 = 3.1415;
	println!("const PI={}",PI);
}

编译错误

error[E0428]: the name `PI` is defined multiple times
 --> main.rs:5:2
  |
3 |     const PI:f32 = 3.14;
  |     -------------------- previous definition of the value `PI` here
4 |     println!("const PI={}",PI);
5 |     const PI:f32 = 3.1415;
  |     ^^^^^^^^^^^^^^^^^^^^^^ `PI` redefined here
  |
  = note: `PI` must be defined only once in the value namespace of this block

error: aborting due to previous error

For more information about this error, try `rustc --explain E0428`.

错误示例2

//设置常量
    const PI:f32 = 3.14;
	println!("const PI={}",PI);
	let PI:f32 = 3.1415;
	println!("let PI={}",PI);

编译错误

warning: floating-point types cannot be used in patterns
 --> main.rs:5:6
  |
5 |     let PI:f32 = 3.1415;
  |         ^^
  |
  = note: `#[warn(illegal_floating_point_literal_pattern)]` on by default
  = warning: this was previously accepted by the compiler but is being phased out; it will become a hard error in a future release!
  = note: for more information, see issue #41620 <https://github.com/rust-lang/rust/issues/41620>

error[E0005]: refutable pattern in local binding: `_` not covered
 --> main.rs:5:6
  |
3 |     const PI:f32 = 3.14;
  |     -------------------- constant defined here
4 |     println!("const PI={}",PI);
5 |     let PI:f32 = 3.1415;
  |         ^^
  |         |
  |         interpreted as a constant pattern, not a new variable
  |         help: introduce a variable instead: `pi_var`

warning: floating-point types cannot be used in patterns
 --> main.rs:5:6
  |
5 |     let PI:f32 = 3.1415;
  |         ^^
  |
  = warning: this was previously accepted by the compiler but is being phased out; it will become a hard error in a future release!
  = note: for more information, see issue #41620 <https://github.com/rust-lang/rust/issues/41620>

error: aborting due to previous error

For more information about this error, try `rustc --explain E0005`.

常量不能推导类型需要确定类型,必须明确类型。吐槽:推导类型应该不难吧,纯粹就是为了瘸一班的感觉!

错误示例

//设置常量
    const PI = 3.14;
	println!("const PI={}",PI);

编译错误

error: missing type for `const` item
 --> main.rs:3:11
  |
3 |     const PI = 3.14;
  |           ^^ help: provide a type for the item: `PI: f64`

error: aborting due to previous error

常量可以在函数外部定义,而可变量和不可变量不可以。
正确示例

//设置常量
const PI:f32 = 3.14;
fn main(){
	println!("const PI={}",PI);
}

运行结果

const PI=3.14

错误示例

//设置
let PI:f32 = 3.14;
fn main(){
	println!("const PI={}",PI);
}

编译错误

error: expected item, found keyword `let`
 --> main.rs:2:1
  |
2 | let PI:f32 = 3.14;
  | ^^^ expected item

error: aborting due to previous error

总结

rust分为可变变量、不可变变量、常量,默认创建的变量为不可变量。

posted @ 2020-03-23 14:20  我想嘿嘿  阅读(941)  评论(0编辑  收藏  举报