//求解复数组 中模较大的N个数
void fianN_Complex(Complex outVec[], int& len, std::vector<int>& index,int N) // Complex (&outVec)[512] 数组引用 单纯数组做参数退化为指针
{
std::vector<double> modulus;
for (size_t i = 0; i < len; i++)
{
double temp;
temp=sqrt(outVec[i].im*outVec[i].im + outVec[i].rl*outVec[i].rl);
modulus.push_back(temp);
}
if (index.size()<N)
{
if (index.size()!=0)
{
for (size_t i = 0; i < index.size(); i++)
{
modulus[index[i]] = 0;
}
}
int indextemp = 0;
for (size_t j = 0; j < modulus.size() - 1; j++)
{
if (modulus[j]>modulus[j + 1])
{
double temp = modulus[j];
modulus[j] = modulus[j + 1];
modulus[j + 1] = temp;
}
else
{
indextemp = j + 1;
}
}
index.push_back(indextemp);
}
}