.cs

if(!Page.IsPostBack)
    {
     //Bind();
      this.TextBox1.Attributes.Add("onkeydown","SubmitKeyClick('Button1');");
     this.TextBox2.Attributes.Add("onkeydown","SubmitKeyClick('Button1');");
    
    }

.aspx]

<SCRIPT LANGUAGE="JavaScript">
    function SubmitKeyClick(button)
    {    
     if (event.keyCode == 13)
     {        
      event.keyCode=9;
      event.returnValue = false;
      document.all[button].click();
     }
    }
   </SCRIPT>

Posted on 2008-10-31 22:10  Yongming Ye  阅读(152)  评论(0)    收藏  举报