前向算法

A = [[0.5, 0.2, 0.3],
[0.3, 0.5, 0.2],
[0.2, 0.3, 0.5]]

B = [[0.5, 0.5],
[0.4, 0.6],
[0.7, 0.3]]

pi = [0.2, 0.4, 0.4]

def a1():
t = 0
a = []
for i in range(len(pi)):
a.append(pi[i] * B[i][t])
return a
a = a1()
print(a)

def q(a, t):
b = []
for i in range(len(A)):
c = 0
for j in range(len(A)):
c += A[j][i] * a[j]
b.append(c*B[i][t])
print(b)
return b

d = q(a, 1)
d = q(d, 0)
posted @ 2022-10-31 10:41  记录——去繁就简  阅读(44)  评论(0)    收藏  举报