Let the Balloon Rise

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you.

InputInput contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.
OutputFor each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input

5
green
red
blue
red
red
3
pink
orange
pink
0

Sample Output

red
pink


找颜色最多的输出

#include <stdio.h>
#include <string.h>
int main()
{
int n, i, j, a[1000]; // 用数组 a来记录 颜色出现的次数
char color[1000][15];
while( scanf("%d", &n) != 0)
{
if( n == 0)
break;

else
{
a[0] = 1;
scanf("%s", color[0]); //先输入第一个颜色
for(i = 1; i < n; i++)
{
a[i] = 1;
scanf("%s",color[i]); //输入第n个元素然后不断和前面的颜色进行比较有相同就 +1
for(j = 0; j < i; j++)
if(strcmp(color[i],color[j]) == 0) a[i] += 1;
}
int max = 0;
int t = 0;
for(i = 1;i < n;i++)
if( max < a[i]) //找出出现次数最多的颜色
{
max = a[i];
t = i;}
printf("%s\n",color[t]);
}
}
}