实验7

实验任务1

源代码

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include <stdio.h>
 3 
 4 #define N 80
 5 #define M 100
 6 
 7 typedef struct {
 8     char name[N];
 9     char author[N];
10 }Book;
11 
12 void write();
13 void read();
14 
15 int main() {
16     printf("测试1：把图书信息写入文本文件\n");
17     write();
18 
19     printf("\n测试2：从文本文件读取图书信息，打印输出到屏幕\n");
20     read();
21 
22     return 0;
23 }
24 
25 void write() {
26     Book x[] = { {"《雕塑家》", "斯科特.麦克劳德"},
27                  {"《灯塔》", "克里斯多夫.夏布特"},
28                  {"《人的局限性》", "塞缪尔.约翰生"},
29                  {"《永不停步：玛格丽特.阿特伍德传》", "罗斯玛丽.沙利文"},
30                  {"《大地之上》", "罗欣顿·米斯特里"},
31                  {"《上学记》", "何兆武"},
32                  {"《命运》", "蔡崇达"} };
33     int n, i;
34     FILE* fp;
35 
36     n = sizeof(x) / sizeof(x[0]);
37 
38     fp = fopen("datal.txt", "w");
39 
40     if (fp == NULL) {
41         printf("fail to open file to write\n");
42         return;
43     }
44 
45     for (i = 0; i < n; ++i)
46         fprintf(fp, "%-40s %-20s\n", x[i].name, x[i].author);
47 
48     fclose(fp);
49 }
50 
51 void read() {
52     Book x[M];
53     int i, n;
54 
55     FILE* fp;
56 
57     fp = fopen("datal.txt", "r");
58 
59     if (fp == NULL) {
60         printf("fail to open file to read\n");
61         return;
62     }
63 
64     i = 0;
65     while (fscanf(fp, "%s%s", x[i].name, x[i].author) != EOF)
66     ++i;
67 
68     n = i;
69     for (i = 0; i < n; ++i)
70         printf("%d. %-40s%-20s\n", i + 1, x[i].name, x[i].author);
71 
72     fclose(fp);
73 }
1

运行结果

777.2

777,1

 

实验任务2

源代码

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include <stdio.h>
 3 
 4 #define N 80
 5 #define M 100
 6 
 7 typedef struct {
 8     char name[N];
 9     char author[N];
10 }Book;
11 
12 void write();
13 void read();
14 
15 int main() {
16     printf("测试1：把图书信息以数据块方式写入二进制文件\n");
17     write();
18 
19     printf("\n测试2：从二进制文件读取图书信息，打印输出到屏幕\n");
20     read();
21 
22     return 0;
23 }
24 
25 void write() {
26     Book x[] = { {"《雕塑家》", "斯科特.麦克劳德"},
27                  {"《灯塔》", "克里斯多夫.夏布特"},
28                  {"《人的局限性》", "塞缪尔.约翰生"},
29                  {"《永不停步：玛格丽特.阿特伍德传》", "罗斯玛丽.沙利文"},
30                  {"《大地之上》", "罗欣顿·米斯特里"},
31                  {"《上学记》", "何兆武"},
32                  {"《命运》", "蔡崇达"} };
33     int n, i;
34     FILE* fp;
35 
36     n = sizeof(x) / sizeof(x[0]);
37 
38     fp = fopen("data2.dat", "wb");
39 
40     if (fp == NULL) {
41         printf("fail to open file to write\n");
42         return;
43     }
44 
45     fwrite(x, sizeof(Book), n, fp);
46 
47     fclose(fp);
48 }
49 
50 void read() {
51     Book x[M];
52     int i, n;
53 
54     FILE* fp;
55 
56     fp = fopen("data2.dat", "rb");
57 
58     if (fp == NULL) {
59         printf("fail to open to read\n");
60         return;
61     }
62 
63     i = 0;
64     while (fread(&x[i], sizeof(Book), 1, fp) == 1)
65         ++i;
66 
67     n = i;
68     for (i = 0; i < n; ++i)
69         printf("%d. %-40s%-20s\n", i + 1, x[i].name, x[i].author);
70 
71     fclose(fp);
72 }
2

运行结果

7777777777777.2

7777777.1

 

实验任务3

源代码

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include <stdio.h>
 3 
 4 #define N 100
 5 #define M 80
 6 
 7 void write();
 8 void read_str();
 9 void read_char();
10 
11 int main() {
12     printf("测试1：把一组字符信息以字符串方式写入文本文件\n");
13     write();
14 
15     printf("\n测试2：从文件以字符串方式读取，输出到屏幕\n");
16     read_str();
17 
18     printf("\n测试3：从文件以单个字符方式读取，输出到屏幕\n");
19     read_char();
20 
21     return 0;
22 }
23 
24 void write() {
25     char* ptr[] = { "Working\'s Blues",
26                   "Everything Will Flow",
27                   "Streets of London",
28                   "Perfect Day",
29                   "Philadelphia" };
30     int i, n;
31     FILE* fp;
32 
33     fp = fopen("data3.txt", "w");
34     if (fp == NULL) {
35         printf("fail to open file to write\n");
36         return;
37     }
38 
39     n = sizeof(ptr) / sizeof(ptr[0]);
40 
41     for (i = 0; i < n; ++i) {
42         fputs(ptr[i], fp);
43         fputs("\n", fp);
44     }
45 
46     fclose(fp);
47 }
48 
49 void read_str() {
50     char songs[N][M];
51     int i, n;
52     FILE* fp;
53 
54     fp = fopen("data3.txt", "r");
55     if (fp == NULL) {
56         printf("fail to open file to read\n");
57         return;
58     }
59 
60     i = 0;
61     while (i < N && (fgets(songs[i], M, fp) != NULL))
62         ++i;
63 
64     n = i;
65     for (i = 0; i < n; ++i)
66         printf("%d. %s", i + 1, songs[i]);
67 
68     fclose(fp);
69 }
70 
71 void read_char() {
72     int ch;
73     FILE* fp;
74 
75     fp = fopen("data3.txt", "r");
76     if (fp == NULL) {
77         printf("fail to open file to read\n");
78         return;
79     }
80 
81     while ((ch = fgetc(fp)) != EOF)
82         putchar(ch);
83 
84     fclose(fp);
85 }
3

运行结果

111111q

qqq

问题

1）\’是转义字符，表示输出'

2)i<N的作用是防止数组越界

 

实验任务4

源代码

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include <stdio.h>
 3 
 4 void write();
 5 void read_line_chars();
 6 
 7 int main() {
 8     printf("data4.txt统计结果:\n");
 9     write();
10     read_line_chars();
11 
12     return 0;
13 }
14 
15 void write() {
16     char* ptr[] = { "0123456789-0123456789",
17                     "nuist2025",
18                     "cosmos galaxy" };
19     int i, n;
20     FILE* fp;
21 
22     fp = fopen("data4.txt", "w");
23     if (fp == NULL) {
24         printf("fail to open file to write\n");
25         return;
26     }
27     n = sizeof(ptr) / sizeof(ptr[0]);
28 
29     for (i = 0; i < n; ++i) {
30         fputs(ptr[i], fp);
31         fputs("\n", fp);
32     }
33 
34     fclose(fp);
35 }
36 
37 void read_line_chars() {
38     int ch;
39     int line = 0;
40     int cha = 0;
41     FILE* fp;
42 
43     fp = fopen("data4.txt", "r");
44     if (fp == NULL) {
45         printf("fail to open file to read\n");
46         return;
47     }
48 
49     while ((ch = fgetc(fp)) != EOF) {
50         if (ch == '\n') {
51             line++;
52         }
53 
54         if (ch != ' ' && ch != '\t' && ch != '\r' && ch != '\n') {
55             cha++;
56         }
57      
58     }
59 
60     printf("行数：              %d\n", line);
61     printf("字符数(不计空白符)：%d\n", cha);
62     fclose(fp);
63 }
4

运行结果

4的截图

运行结果4

 

实验任务5

源代码

  1 #define _CRT_SECURE_NO_WARNINGS
  2 #include <stdio.h>
  3 #include <string.h>
  4 
  5 #define N 10
  6 
  7 typedef struct {
  8     long id;
  9     char name[20];
 10     float objective;
 11     float subjective;
 12     float sum;
 13     char result[10];
 14 }STU;
 15 
 16 void read(STU st[], int n);
 17 void write(STU st[], int n);
 18 void output(STU st[], int n);
 19 int process(STU st[], int n, STU st_pass[]);
 20 
 21 int main() {
 22     STU stu[N], stu_pass[N];
 23     int cnt;
 24     double pass_rate;
 25 
 26     printf("\n从文件读入%d个考生信息...\n", N);
 27     read(stu, N);
 28 
 29     printf("\n对考生成绩进行统计...\n");
 30     cnt = process(stu, N, stu_pass);
 31 
 32     printf("\n通过考生的名单：\n");
 33     output(stu, N);
 34     write(stu_pass,cnt);
 35 
 36     pass_rate = 1.0 * cnt / N;
 37     printf("\n本次考试通过率:%.2f%%\n", pass_rate * 100);
 38 
 39     return 0;
 40 }
 41 
 42 void output(STU st[], int n) {
 43     int i;
 44 
 45     printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n");
 46     for (i = 0; i < n; i++)
 47         printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", st[i].id, st[i].name,
 48             st[i].objective, st[i].subjective, st[i].sum, st[i].result);
 49 }
 50 
 51 void read(STU st[], int n) {
 52     int i;
 53     FILE* fin;
 54 
 55     fin = fopen("examinee.txt", "r");
 56     if (!fin) {
 57         printf("fail to open file\n");
 58         return;
 59     }
 60 
 61     for(i=0;i<n;i++)
 62         fscanf(fin, "%ld %s %f %f", &st[i].id, st[i].name, &st[i].objective,
 63             &st[i].subjective);
 64 
 65     fclose(fin);
 66 }
 67 
 68 void write(STU st[], int n) {
 69     int i;
 70     FILE* fp;
 71 
 72     fp = fopen("list_pass.txt", "w");
 73     if (!fp) {
 74         printf("fail to open file to write\n");
 75         return;
 76     }
 77 
 78     fprintf(fp, "准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n");
 79     for (i = 0; i < n; ++i) {
 80         fprintf(fp,"%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", st[i].id, st[i].name,
 81             st[i].objective, st[i].subjective, st[i].sum, st[i].result);
 82     }
 83     fclose(fp);
 84 }
 85 
 86 int process(STU st[], int n, STU st_pass[]) {
 87     int i;
 88     int pass = 0;
 89 
 90     for (i = 0; i < n; ++i) {
 91         st[i].sum = st[i].objective + st[i].subjective;
 92         if (st[i].sum >= 60) {
 93             strcpy(st[i].result, "通过");
 94             st_pass[pass++] = st[i];
 95         }
 96         else {
 97             strcpy(st[i].result, "未通过");
 98         }
 99     }
100 
101     return pass;
102 }
5

运行结果

烫烫烫

一直在烫烫烫QAQ

 

实验任务6

源代码

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include <stdio.h>
 3 #include <stdlib.h>
 4 #include <time.h>
 5 #include <string.h>
 6 #define N 100  
 7 #define M 5   
 8 
 9 int main() {
10     char s[N][N];      
11     int has_hit[N] = { 0 };
12     char hit[N][N];    
13     FILE* fp, * fout;
14     int i, n;
15     char filename[80];
16     int lucky_i;
17     char tmp[80];    
18 
19     fp = fopen("C:\\Users\\asus\\Desktop\\新建文件夹 (2)\\list.txt", "r");
20     if (!fp) {
21         perror("list.txt");
22         return 1;
23     }
24 
25     i = 0;
26     while (fgets(s[i], N, fp) != NULL) {
27         s[i][strcspn(s[i], "\n")] = '\0';
28         ++i;
29     }
30     n = i;
31 
32     srand((unsigned int)time(0));
33     for (i = 0; i < M; ) {
34         lucky_i = rand() % n;  
35         if (has_hit[lucky_i])  
36             continue;
37         has_hit[lucky_i] = 1;
38         strcpy(hit[i], s[lucky_i]);
39         ++i;
40     }
41 
42     printf("-------------------中奖名单-------------------\n");
43     for (i = 0; i < M; ++i) {
44         printf("%s\n", hit[i]);
45     }
46     printf("-------------保存到文件------------");
47 
48     printf("\n输入文件名：");
49     fgets(tmp, 80, stdin);
50     tmp[strcspn(tmp, "\n")] = '\0';
51     strcpy(filename, tmp);
52 
53     fout = fopen(filename, "w");
54     if (!fout) {
55         perror(filename);
56         fclose(fp);
57         return 1;
58     }
59     for (i = 0; i < M; ++i) {
60         fprintf(fout, "%s\n", hit[i]);
61     }
62 
63     printf("保存成功！\n");
64 
65     fclose(fp);
66     fclose(fout);
67 
68     return 0;
69 }
6

运行结果

1229

zzzzzzz

 

posted @ 2025-12-29 22:33  辣椒酱拌芥末  阅读(7)  评论(0)    收藏  举报