最少步数(BFS)
又是简单的搜索题,不过我的代码能力太差了,一道题,只是写代码就花了哥很长时间去调试,~\(≧▽≦)/~啦啦啦
http://59.69.128.200/JudgeOnline/problem.php?pid=58
#include <iostream>
#include<cstdio>
#include <queue>
#include<string.h>
using namespace std;
int si,sj,ei,ej;
int dir[][2]={{0,1},{0,-1},{1,0},{-1,0},{1,1},{1,-1},{-1,1},{-1,-1}};
struct node{
int x,y,num;
node(int xx=0,int yy=0,int nn=0){x=xx;y=yy;num=nn;}
};
int bfs(int mat[][9])
{
int bu;
queue<node> Q;
node fr;
mat[si][sj]=1;
Q.push(node(si,sj,0));
while(!Q.empty())
{
fr=Q.front();
Q.pop();
if(fr.x==ei&&fr.y==ej)
return fr.num;
for(int i=0;i<4;i++)
{
int ii=fr.x+dir[i][0],jj=fr.y+dir[i][1];
if(ii>=0&&jj>=0&&ii<9&&jj<9&&mat[ii][jj]==0)
{
Q.push(node(ii,jj,fr.num+1));
mat[ii][jj]=1;
}
}
}
}
int main()
{
int n;
scanf("%d",&n);
while(n--)
{
int mat[9][9]={
1,1,1,1,1,1,1,1,1,
1,0,0,1,0,0,1,0,1,
1,0,0,1,1,0,0,0,1,
1,0,1,0,1,1,0,1,1,
1,0,0,0,0,1,0,0,1,
1,1,0,1,0,1,0,0,1,
1,1,0,1,0,1,0,0,1,
1,1,0,1,0,0,0,0,1,
1,1,1,1,1,1,1,1,1};
scanf("%d%d%d%d",&si,&sj,&ei,&ej);
printf("%d\n",bfs(mat));
}
}
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