MySQL_Sql_打怪升级_进阶篇_进阶3:排序查询

进阶3:排序查询

语法:

select 
  查询列表 
from
  表名 
where 筛选条件 
order by 排序的字段或表达式 ;

特点:

1. asc    代表的是升序,可以省略 ,默认是升序排序
   desc   代表的是降序
2. order by 子句可以支持 单个字段、别名、表达式、函数、多个字段
3. order by 子句在查询语句的最后面,除了limit子句

3.1查询员工信息,要求工资从高到低排序

SELECT * FROM employees ORDER BY salary DESC;

3.2添加筛选条件再排序

案例:查询部门编号>=90的员工信息,并按员工编号降序

SELECT *
FROM employees
WHERE department_id>=90
ORDER BY employee_id DESC;

3.3按表达式排序

案例:查询员工信息 按年薪降序

SELECT *,salary*12*(1+IFNULL(commission_pct,0))
FROM employees
ORDER BY salary*12*(1+IFNULL(commission_pct,0)) DESC;

3.4按别名排序

案例:查询员工信息 按年薪升序

SELECT *,salary*12*(1+IFNULL(commission_pct,0)) 年薪
FROM employees
ORDER BY 年薪 ASC;

3.5按函数排序

案例:查询员工名,并且按名字的长度降序 [函数length]

SELECT LENGTH(last_name),last_name 
FROM employees
ORDER BY LENGTH(last_name) DESC;

3.6按多个字段排序

案例:查询员工信息,要求先按工资降序,再按employee_id升序

SELECT *
FROM employees
ORDER BY salary DESC,employee_id ASC;

3.7排序查询习题

#1.查询员工的姓名和部门号和年薪,按年薪降序 按姓名升序
SELECT last_name,department_id,salary*12*(1+IFNULL(commission_pct,0)) 年薪
FROM employees
ORDER BY 年薪 DESC,last_name ASC;

#2.选择工资不在8000到17000的员工的姓名和工资,按工资降序
SELECT last_name,salary
FROM employees
WHERE salary NOT BETWEEN 8000 AND 17000
ORDER BY salary DESC;

#3.查询邮箱中包含e的员工信息,并先按邮箱的字节数降序,再按部门号升序
SELECT *,LENGTH(email)
FROM employees
WHERE email LIKE '%e%'
ORDER BY LENGTH(email) DESC,department_id ASC;
posted @ 2020-09-02 23:46  oldliych  阅读(236)  评论(0编辑  收藏  举报