实验6

实验4：

源码：

#include<stdio.h>
#include<stdlib.h>
#define N 10

typedef struct{
    char isbn[20];
    char name[80];
    char author[80];
    double sales_price;
    int sales_count;
}Book;

void output(Book x[],int n);
void sort(Book x[],int n);
double sales_amount(Book x[],int n);

int main(){
    Book x[N]={{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
               {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
               {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
               {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
               {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
               {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
               {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
               {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
               {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊 奇", 37.5, 55},
               {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    printf("图书销量排名（按销售册数）：\n");
    sort(x,N);
    output(x,N);

    printf("\n图书销售总额：%.2f\n",sales_amount(x,N));

    system("pause");
    return 0;
}
void output(Book x[],int n){
    int i;
    printf("ISBN号               书名                           作者                 售价                 销售册数               \n");
    for(i=0;i<n;i++)
        printf("%-20s %-30s %-20s %-20g %-20d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}

void sort(Book x[],int n){
    int i,j;
    Book t;
    for(i=0;i<n-1;i++)
        for(j=0;j<n-1-i;j++){
            if(x[j].sales_count<x[j+1].sales_count){
                t=x[j];    
                x[j]=x[j+1];
                x[j+1]=t;
            }
        }
}

double sales_amount(Book x[],int n){
    double sum=0;
    int i;
    for(i=0;i<n;i++)
        sum+=x[i].sales_count*x[i].sales_price;
    return sum;
}

截图：

实验5：

源码：

#include<stdio.h>
#include<stdlib.h>

typedef struct{
    int year;
    int month;
    int day;
}Date;

void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);

void test1(){
    Date d;
    int i;

    printf("输入日期：（以形如2024-12-16这样的形式输出）\n");
    for(i=0;i<3;i++){
        input(&d);
        printf("%d-%02d-%02d是这一年中的第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
    }
}

void test2(){
    Date Alice_birth,Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob的出生日期：（以形如2024-12-16这样的形式输入）\n");
    for(i=0;i<3;i++){
        input(&Alice_birth);
        input(&Bob_birth);
        ans=compare_dates(Alice_birth,Bob_birth);

        if(ans==0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1) 
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main(){
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
    system("pause");
    return 0;
}

void input(Date *pd){
    scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}

int day_of_year (Date d){
    int sum=0;
    if((d.year%4==0&&d.year%100!=0)||(d.year%400==0)){
        switch(d.month){
            case 12:
                sum+=335;break;
            case 11:
                sum+=305;break;
            case 10:
                sum+=274;break;
            case 9:
                sum+=244;break;
            case 8:
                sum+=213;break;
            case 7:
                sum+=182;break;
            case 6:
                sum+=152;break;
            case 5:
                sum+=121;break;
            case 4:
                sum+=91;break;
            case 3:
                sum+=60;break;
            case 2:
                sum+=31;break;
        }
    }
    else{
        switch(d.month){
            case 12:
                sum+=334;break;
            case 11:
                sum+=304;break;
            case 10:
                sum+=273;break;
            case 9:
                sum+=243;break;
            case 8:
                sum+=212;break;
            case 7:
                sum+=181;break;
            case 6:
                sum+=151;break;
            case 5:
                sum+=120;break;
            case 4:
                sum+=90;break;
            case 3:
                sum+=59;break;
            case 2:
                sum+=31;break;
        }
    }
    return sum+d.day;
}

int compare_dates(Date d1,Date d2){
    if(d1.year>d2.year)
        return 1;
    else if(d1.year<d2.year)
        return -1;
    else{
        if(d1.month>d2.month)
            return 1;
        else if(d1.month<d2.month)
            return -1;
        else{
            if(d1.day>d2.day)
                return 1;
            if(d1.day<d2.day)
                return -1;
            else
                return 0;
        }
    }
}

截图：

实验6：

源码：

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

enum Role{admin,student,teacher};

typedef struct{
    char username[20];
    char password[20];
    enum Role type;
}Account;

void output(Account x[],int n);

int main(){
    Account x[]={{"A1001", "123456", student},
                 {"A1002", "123abcdef", student},                 
                 {"A1009", "xyz12121", student},
                 {"X1009", "9213071x", admin},
                 {"C11553", "129dfg32k", teacher},
                 {"X3005", "921kfmg917", student}};
    int n;
    n=sizeof(x)/sizeof(Account);
    output(x,n);

    system("pause");
    return 0;
}

void output(Account x[],int n){
    int i,j;
    for(i=0;i<n;i++){
        for(j=0;j<strlen(x[i].password);){
                x[i].password[j++]='*';
        }
    }
    for(i=0;i<n;i++){
        printf("%-20s",x[i].username);
        printf("%-20s",x[i].password);
        if(x[i].type==admin)
            printf("admin\n");
        else if(x[i].type==student)
            printf("student\n");
        else
            printf("teacher\n");
    }
}

截图：

实验7：

源码：

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

typedef struct{
    char name[20];
    char phone[12];
    int vip;
}Contact;

void set_vip_contact(Contact x[],int n,char name[]);
void output(Contact x[],int n);
void display(Contact x[],int n);

#define N 10
int main(){
    Contact list[N]={{"刘一", "15510846604", 0},
                     {"陈二", "18038747351", 0},
                     {"张三", "18853253914", 0},
                     {"李四", "13230584477", 0},
                     {"王五", "15547571923", 0},
                     {"赵六", "18856659351", 0},
                     {"周七", "17705843215", 0},
                     {"孙八", "15552933732", 0},
                     {"吴九", "18077702405", 0},
                     {"郑十", "18820725036", 0}};
    int vip_cnt,i;
    char name[20];

    printf("显示原始通讯录信息：\n");
    output(list,N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d",&vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for(i=0;i<vip_cnt;i++){
        scanf("%s",name);
        set_vip_contact(list,N,name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);

    system("pause");
    return 0;
}

void set_vip_contact(Contact x[],int n,char name[]){
    int i;
    for(i=0;i<n;i++)
        if(strcmp(x[i].name,name)==0)
            x[i].vip=1;
}

void display(Contact x[],int n){
    int i,j,m,count=0;
    Contact t;
    for(i=0;i<n;i++)
        if(x[i].vip==1){
            t=x[i];
            x[i]=x[count];
            x[count++]=t;
        }
    for(i=0;i<count-1;i++)
        for(j=0;j<count-1-i;j++)
            if(strcmp(x[j].name,x[j+1].name)>0){
                t=x[j];
                x[j]=x[j+1];
                x[j+1]=t;
            }
    for(i=count;i<n-1;i++)
        for(j=count;j<n-i-1+count;j++)
            if(strcmp(x[j].name,x[j+1].name)>0){
                t=x[j];
                x[j]=x[j+1];
                x[j+1]=t;
            }
    output(x,n);
}

void output(Contact x[],int n){
    int i;
    for(i=0;i<n;i++){
        printf("%-10s %15s",x[i].name,x[i].phone);
        if(x[i].vip)
            printf("%5s","*");
        printf("\n");
    }
}

截图：