计算两条直线的交点--C语言

呵呵，有点急。。。

#include<stdio.h>

typedef struct point{
    int x;
    int y;
}point;

typedef struct line{
    point point1;
    point point2;
}line;

//计算两条直线的交点
point getCross(line line1, line line2)
{
    point CrossP;
    //y = a * x + b;
    int a1 = (line1.point1.y - line1.point2.y) / (line1.point1.x - line1.point2.x);
    int b1 = line1.point1.y - a1 * (line1.point1.x);

    int a2 = (line2.point1.y - line2.point2.y) / (line2.point1.x - line2.point2.x);
    int b2 = line2.point1.y - a1 * (line2.point1.x);

    CrossP.x = (b1 - b2) / (a2 - a1);
    CrossP.y = a1 * CrossP.x + b1;
    return CrossP;
}

void main()
{
    line line1;
    line line2;

    //line1
    line1.point1.x = 10;
    line1.point1.y = 10;
    line1.point2.x = 50;
    line1.point2.y = 50;

    //line2
    line2.point1.x = 2;
    line2.point1.y = 60;
    line2.point2.x = 60;
    line2.point2.y = 0;

    point CointP = getCross(line1, line2);
    printf("%d,%d\n", CointP.x, CointP.y);

}