http://codeforces.com/contest/284/problem/D
dp+记忆化搜索
代码:
#include<iostream>
#include<cmath>
#include<cstdio>
#include<string>
#include<cstring>
#include<vector>
#include<stack>
#include<queue>
#include<map>
#include<set>
#include<algorithm>
#define LL long long
using namespace std;
const int INF=0x3f3f3f3f;
const int N=200005;
long long inc[N],decr[N];
int had1[N],had2[N];
int a[N];
int n;
long long dpdecr(int x,int k);
long long dpinc(int x,int k)
{//cout<<"inc "<<x<<" "<<k<<endl;
if(x<=0||x>n)
return 0;
if(had1[x]==k)
return -1;
if(inc[x]!=-2)
return inc[x];
had1[x]=k;
long long tmp=dpdecr(x+a[x],k);
if(tmp==-1)
return (inc[x]=-1);
return (inc[x]=tmp+a[x]);
}
long long dpdecr(int x,int k)
{//cout<<"decr "<<x<<" "<<k<<endl;
if(x<=0||x>n)
return 0;
if(had2[x]==k)
return -1;
if(decr[x]!=-2)
return decr[x];
had2[x]=k;
long long tmp=dpinc(x-a[x],k);
if(tmp==-1)
return (decr[x]=-1);
return (decr[x]=tmp+a[x]);
}
int main()
{
//freopen("data.in","r",stdin);
while(cin>>n)
{
for(int i=2;i<=n;++i)
cin>>a[i];
memset(had1,0,sizeof(had1));
memset(had2,0,sizeof(had2));
for(int i=1;i<=n;++i)
inc[i]=decr[i]=-2;
inc[1]=-1;
decr[1]=0;
for(int i=2;i<=n;++i)
{
long long k=dpdecr(i,i);
if(k==-1)
cout<<"-1"<<endl;
else
cout<<(k+i-1)<<endl;
}
}
return 0;
}
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