摘要：
``` x<-seq(-1.1,1.1,length = 3000) rep<-30 y<-matrix(,3000,rep) yx<-matrix(,3000,rep) xx<-matrix(,3000,rep) c<-seq(0,1,length=rep) for (i in 1:rep) for (p in 1:3000){ y[p,i]<-(1-(x[p])^2)^(1/2)+((x[p]... 阅读全文
posted @ 2015-09-08 21:15
liuhui_pine
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