php精简日历

<table>
	<caption>
		<?=date('Y年m月')?>
	</caption>
	<thead>
		<tr>
			<th scope="col" title="星期一">一</th>
			<th scope="col" title="星期二">二</th>
			<th scope="col" title="星期三">三</th>
			<th scope="col" title="星期四">四</th>
			<th scope="col" title="星期五">五</th>
			<th scope="col" title="星期六">六</th>
			<th scope="col" title="星期日">日</th>
		</tr>
	</thead>

	<!-- <tfoot>
		<tr>
			<td colspan="3" id="prev"><a href="/blog/888?m=201210" title="查看 2012 年十月的文章">« 十</a></td>
			<td class="pad"> </td>
			<td colspan="3" id="next" class="pad"> </td>
		</tr>
	</tfoot> -->
	<tbody>
	<?php
	$stamp = strtotime('-'.date('j').' days'); //月第一天的时间戳
	$total_days = date('t',$stamp);//月共有天数
	$week_day = date('N',$stamp);//周几1-7
	$calendar = '';
	for($i=1; $i<$total_days+$week_day; $i++){
		$calendar .= ($i==1) ? '<tr>' : '';
		
		if($i<=$week_day){
			$calendar .= '<td></td>';
		}else{
			$stamp = strtotime('next day',$stamp);
			$today = (date('Ymd',$stamp) == date('Ymd')) ? 'id="today"' : '';
			$calendar .= '<td '.$today.'>'.date('d',$stamp).'</td>';
		}
		
		$calendar .= ($i%7==0) ? '</tr><tr>' : '';
		$calendar .= ($i+1 == $total_days+$week_day) ? str_repeat('<td></td>', 7-date('N',$stamp)).'</tr>' : '';
	}
	echo $calendar;
	?>
	</tbody>
</table>