第七次作业

1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。

package task;


import java.util.Iterator;




public class T1 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int a[]= {10,20,30,40,50};
        for (int i = 0; i < a.length; i++) {
            System.out.println(a[i]);
        }
        
        
    
    }
}

2.编写一个简单程序,要求数组长度为5,动态赋值,并在控制台输出该数组的值。

 

package task;


import java.util.Iterator;
import java.util.Scanner;




public class T1 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int a[]=new int[5];
        Scanner input=new Scanner(System.in);
        for (int i = 0; i < a.length; i++) {
            a[i]=input.nextInt();
        }
        
        for (int i = 0; i < a.length; i++) {
            System.out.println(a[i]);
        }
        
        
    
    }
}


3.定义字符型数组,分别存储c、h、 i、n、a 并在控制台输出

package task;


import java.util.Iterator;
import java.util.Scanner;




public class T1 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
         char a[]= {'c','h','i','n','a'};
            for (int i = 0; i < a.length; i++) {
                System.out.println(a[i]);
            }
        
    
    }
}


4.输入5个学生成绩,求总分和平均分

 

package task;


import java.util.Iterator;
import java.util.Scanner;




public class T1 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int sum=0;
        int p=0;
        int a[]=new int[5];
        Scanner input=new Scanner(System.in);
        for (int i = 0; i < a.length; i++) {
            a[i]=input.nextInt();
        }
        
        for (int i = 0; i < a.length; i++) {
           sum+=a[i];
        }
        System.out.println(sum);
        System.out.println(sum/5);
    
    }
}

 

 

 


5.定义数组{12,53,23,44,53} 用for和foreach分别输出,再倒序输出

package task;


import java.util.Iterator;
import java.util.Scanner;




public class T1 {

    public static void main(String[] args) {
        int a[]= {12,53,23,44,53};
        for (int j = 0; j < 5; j++) {
             System.out.print(","+a[j]);
        }
        System.out.println();
           for (int j = 4; j >= 0; j--) {
               System.out.print(","+a[j]);
            
        }
        
    
    }
}

 

 

 


作业:
1.定义一个整型数组,赋值后求出奇数个数和偶数个数

package task;


import java.util.Iterator;
import java.util.Scanner;




public class T1 {

    public static void main(String[] args) {
        int b=0;
        int c=0;
        int a[]= {12,53,23,44,53};
        for (int j = 0; j < 5; j++) {
            if (a[j]%2==0) {
                b++;
            } else {
                c++;

            }
        }
        System.out.println("奇数有"+c+"个");
          
        System.out.println("偶数有"+b+"个");
    
    }
}

 

 

 


2.生成一个100长度数组,里面的数分别是1-100,并输出

 

package task;


import java.util.Iterator;
import java.util.Scanner;




public class T1 {

    public static void main(String[] args) {
        
         int []a=new int[100];
            for (int i = 0; i < 100; i++) {
            a[i]=i+1;
                System.out.println(a[i]);
            }
        
    
    }
}

 

 

 

 


3.定义一个double数组,存放10个学生的成绩,给所有同学加5分,不能超过100分。

package task;


import java.util.Iterator;
import java.util.Scanner;




public class T1 {

    public static void main(String[] args) {
        
         int a[]=new int[10];
            Scanner input=new Scanner(System.in);
            for (int i = 0; i < a.length; i++) {
                a[i]=input.nextInt();
                if (a[i]>100||a[i]<0) {
                        System.out.println("从新输入");
                        a[i]=input.nextInt();
                    }
            }
            
            for (int i = 0; i < a.length; i++) {
                if (a[i]>96) {
                    System.out.println(100);
                    
                }
                else{
                System.out.println(a[i]+5);
            }
            }
        
    
    }
}

 

posted @ 2021-04-20 21:17  柳啊柳啊柳  阅读(26)  评论(0编辑  收藏  举报