HDU 3032 Nim or not Nim (sg函数)

加强版的NIM游戏,多了一个操作,可以将一堆石子分成两堆非空的。

数据范围太大,打出sg表后找规律。

# include <cstdio>
# include <cstring>
# include <cstdlib>
# include <iostream>
# include <vector>
# include <queue>
# include <stack>
# include <map>
# include <set>
# include <cmath>
# include <algorithm>
using namespace std;
# define lowbit(x) ((x)&(-x))
# define pi acos(-1.0)
# define eps 1e-3
# define MOD 1000000007
# define INF 1000000000
# define mem(a,b) memset(a,b,sizeof(a))
# define FOR(i,a,n) for(int i=a; i<=n; ++i)
# define FO(i,a,n) for(int i=a; i<n; ++i)
# define bug puts("H");
# define lch p<<1,l,mid
# define rch p<<1|1,mid+1,r
# define mp make_pair
# define pb push_back
# define fi first
# define se second
typedef pair<int,int> PII;
typedef vector<int> VI;
# pragma comment(linker, "/STACK:1024000000,1024000000")
typedef long long LL;
typedef unsigned long long ULL;
int _MAX(int a, int b){return a>b?a:b;}
int _MIN(int a, int b){return a>b?b:a;}
int Scan() {
    int res=0, flag=0;
    char ch;
    if((ch=getchar())=='-') flag=1;
    else if(ch>='0'&&ch<='9') res=ch-'0';
    while((ch=getchar())>='0'&&ch<='9')  res=res*10+(ch-'0');
    return flag?-res:res;
}
void Out(int a) {
    if(a<0) {putchar('-'); a=-a;}
    if(a>=10) Out(a/10);
    putchar(a%10+'0');
}
const int N=1000005;

int find(int x)
{
    if (x%4==0) return x-1;
    if (x%4==3) return x+1;
    return x;

}
int main ()
{
    int T, n, temp;
    scanf("%d",&T);
    while (T--) {
        scanf("%d",&n);
        int ans=0;
        while (n--) scanf("%d",&temp), ans^=find(temp);
        puts(ans?"Alice":"Bob");
    }
    return 0;
}
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posted @ 2017-01-07 15:06  free-loop  阅读(147)  评论(0编辑  收藏  举报