LeetCode--Reverse Integer 

 1 class Solution:
 2     # @return an integer
 3     def reverse(self, x):
 4         if x < 0 :
 5             a = str(x)
 6             a = filter(str.isdigit,a)
 7             a = a[::-1]
 8             b = int(a)
 9             b = 0 - b
10         else :
11             a = str(x)
12             a = filter(str.isdigit,a)
13             a = a[::-1]
14             b = int(a)
15         return b

 

posted @ 2014-03-23 18:01  laste  阅读(74)  评论(0)    收藏  举报