Remove Element --移除重复元素

Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Example:
Given input array nums = [3,2,2,3], val = 3

Your function should return length = 2, with the first two elements of nums being 2.

题意：只能用常量内存操作；去除与val值相同的元素，返回数组的长度；

思路：和 Remove Duplicates from Sorted Array --移除数组重复元素 思路差不多，只是val的值是给定的；

实现代码如下：

int removeElement(int* nums, int numsSize, int val) {
    int i=0,j;
    for(j = 0;j<numsSize;j++){
        if(nums[j]!=val){
            nums[i++] = nums[j];
        }
    }
    return i;
}