What Is Your Grade?

“Point, point, life of student!”
This is a ballad（歌谣）well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the rules which are used in this course.
There are 5 problems in this final exam. And I will give you 100 points if you can solve all 5 problems; of course, it is fairly difficulty for many of you. If you can solve 4 problems, you can also get a high score 95 or 90 (you can get the former(前者) only when your rank is in the first half of all students who solve 4 problems). Analogically（以此类推）, you can get 85、80、75、70、65、60. But you will not pass this exam if you solve nothing problem, and I will mark your score with 50.
Note, only 1 student will get the score 95 when 3 students have solved 4 problems.
I wish you all can pass the exam!
Come on!
Input
Input contains multiple test cases. Each test case contains an integer N (1<=N<=100, the number of students) in a line first, and then N lines follow. Each line contains P (0<=P<=5 number of problems that have been solved) and T（consumed time）. You can assume that all data are different when 0<p.
A test case starting with a negative integer terminates the input and this test case should not to be processed.
Output
Output the scores of N students in N lines for each case, and there is a blank line after each case.
Sample Input
4
5 06:30:17
4 07:31:27
4 08:12:12
4 05:23:13
1
5 06:30:17
-1
Sample Output
100
90
90
95

100

一开始看错了，写的相同题数的第一个人可以得高分，题意是相同题数前一半可以得高分，把每道题的写对的人数标记一下就可以了，本来写了两个sort，先排时间，后排了题数，第二个是多余的，但是不去掉会wa，原因还是sort反而会使原来的变成乱序，把第二个sort注释掉才过了

#include<iostream>
#include<algorithm>
using namespace std;
struct student{
	int answer;
	int shi;
	int fen;
	int miao;
	int time;
	int score;
	int number;
};
bool cmp1(student a,student b){
	return a.time <b.time ;
}
bool cmp2(student a,student b){
	return a.answer  >b.answer  ;
}
bool cmp3(student a,student b){
	return a.number  <b.number  ;
}
student stu[200];
int main(){
	int t;
	while(cin>>t){
	if(t<1||t>100) break;
	int b[5]={0};
	for(int i=0;i<t;i++){
		stu[i].number =i;
		cin>>stu[i].answer ;
		b[stu[i].answer ]++;
		scanf("%d:%d:%d",&stu[i].shi,&stu[i].fen ,&stu[i].miao  );
		stu[i].time =3600*stu[i].shi +60*stu[i].fen +stu[i].miao ;
	//	cout<<stu[i].answer<<" "; 
	}
	sort(stu,stu+t,cmp1);
//	sort(stu,stu+t,cmp2);
	int a[5]={0};
	int ans=5;
	for(int i=0;i<t;i++){
	//	cout<<stu[i].answer <<" ";
		if(stu[i].answer ==5){
			stu[i].score =100;
		}
		else if(stu[i].answer ==4){
			if(a[4]<b[4]/2){
				stu[i].score =95;
				a[4]++;
			}
			else stu[i].score =90;
		}
		else if(stu[i].answer ==3){
			if(a[3]<b[3]/2){
				stu[i].score =85;
				a[3]++;
			}
			else stu[i].score =80;
		}
		else if(stu[i].answer ==2){
			if(a[2]<b[2]/2){
				stu[i].score =75;
				a[2]++;
			}
			else stu[i].score =70;
		}
		else if(stu[i].answer ==1){
			if(a[1]<b[1]/2){
				stu[i].score =65;
				a[1]++;
			}
			else stu[i].score =60;
		}
		else stu[i].score =50;
	}
	sort(stu,stu+t,cmp3);
	for(int i=0;i<t;i++){
		//cout<<stu[i].number <<" ";
		cout<<stu[i].score <<endl;;
	}
	cout<<endl;
}
	return 0;
}