给一串字符 按奇偶数位输出 

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include<stdio.h>
 3 #include<stdlib.h>
 4 #include<string.h>
 5 
 6 int getStr1Str2(char *source, char *buf1, char *buf2)
 7 {
 8     char *tmpSource = source;
 9     char *tmpBuf1 = buf1;
10     char *tmpBuf2 = buf2;
11 
12     int len = 1;
13 
14     while (*tmpSource!='\0')
15     {
16         if (len % 2)//奇数
17         {
18 
19             *tmpBuf1++ = *tmpSource++;
20             len++;
21         }
22         else
23         {
24             *tmpBuf2++ = *tmpSource++;
25             len++;
26         }
27          
28     }
29     *tmpBuf1 = '\0';
30     *tmpBuf2 = '\0';
31 }
32 int main()
33 {
34     char *source = "1a2b3d4z";
35     char *buf1 = (char*)malloc(100);
36     char *buf2 = (char*)malloc(100);
37     getStr1Str2(source, buf1, buf2);
38     printf("buf1奇数位:%s\n",buf1);
39     printf("buf2偶数位:%s\n", buf2);
40     system("pause");
41     return 0;
42 }

 

posted @ 2015-10-06 14:21  微风星宇  阅读(820)  评论(0)    收藏  举报