JavaScript使用XMLHttpRequest 發送GET/Post 請求
Posted on 2016-10-12 14:06 work hard work smart 阅读(472) 评论(0) 收藏 举报<!DOCTYPE HTML>
<html>
<head>
<title>Demo</title>
<script type="text/javascript">
var xmlHttp;
//XmlHttpRequest对象
function createXMLHttpRequest() {
var xmlHttp;
if (window.XMLHttpRequest) { //非IE浏览器
xmlHttp = new XMLHttpRequest();
if (xmlHttp.overrideMimeType)
xmlHttp.overrideMimeType('text/xml');
} else if (window.ActiveXObject) { //如果是IE浏览器
try {
xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {
}
}
}
return xmlHttp;
}
function getStatusBack(){
if(xmlHttp.readyState == 4 && xmlHttp.status == 200){
var b = xmlHttp.responseText;
alert(b);
console.log(b);
}
}
function testGet(){
xmlHttp = createXMLHttpRequest();
var url = "http://xxx/xxx/xxx"
xmlHttp.open("GET", url, true);// 异步处理返回
xmlHttp.onreadystatechange = getStatusBack; //设置回调函数
xmlHttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded;");
xmlHttp.send(); //发送请求
}
function testPost(){
var parameter = "tidList=1"
var url = "http://xxx/xxx/xxx";
xmlHttp = createXMLHttpRequest();
xmlHttp.open("POST", url, true);
xmlHttp.onreadystatechange = getStatusBack; //设置回调函数
xmlHttp.setRequestHeader("Content-Type",
"application/x-www-form-urlencoded;");
xmlHttp.send(); //发送请求
}
</script>
</head>
<body>
<button onclick="testGet()">Test Get</button>
<button onclick="testPost()">Test Post</button>
</body>
</html>
作者:Work Hard Work Smart
出处:http://www.cnblogs.com/linlf03/
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