java并发计算的几种基本使用示例

通常我们使用程序处理计算,常见的有单线程,JUC下单的多线程,还有优秀的ForkJoin框架(与递归形式上相似却又优于递归),直接上代码吧

 1 package com.fork;
 2 
 3 import java.util.concurrent.ExecutionException;
 4 import java.util.concurrent.ForkJoinPool;
 5 import java.util.concurrent.ForkJoinTask;
 6 import java.util.concurrent.RecursiveTask;
 7 10 
11 public class ForkDemo extends RecursiveTask<Long>{
12     private long end;
13     private final long THRELOD = 500000000L;
14     private  long start;
15     public ForkDemo(long start ,long end) {
16         this.end = end;
17         this.start = start;
18     }
19 
20     @Override
21     protected  Long compute() {
22         long v = 0;
23         if( end - start <= THRELOD) {
24             for (long i = start; i <= end; i++) {
25                 v += i;
26             }
27             return v;
28         }else {
29             long middle = (end + start)/2;
30             ForkDemo demo1 = new ForkDemo(start, middle);
31             ForkDemo demo2 = new ForkDemo(middle+1, end);
32             demo1.fork();
33              demo2.fork();
34             return demo1.join() + demo2.join();
35             
36         }        
37     }
38 }

 

 这是ForkJoin的基本示例使用,以下是三种计算的比较;

package com.fork;

import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.concurrent.Callable;
import java.util.concurrent.ConcurrentHashMap;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.ForkJoinPool;
import java.util.concurrent.ForkJoinTask;
import java.util.concurrent.Future;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;




public class LockDemo {
//	 单线程方式
	public static long execSingle(long n) {
		long sum = 0;
		for (long i = 1; i <= n; i++) {
			sum += i;
		}
		System.out.println("the sum = " + sum);
		return sum;
	}
//	 多线程方式
	 public static long execMult(long n) throws ExecutionException {
		 long value = 0L;
	     ExecutorService exect = Executors.newFixedThreadPool(3);
	     ArrayList<Callable<Long>> list =new ArrayList<Callable<Long>>();
	     long total;
	     list.add(()->{
	        long sum = 0L;
	    	for(Long i=1L;i<=n;i+=3) {
	    		sum += i;
	    	}
	    	return sum;
	    });
	     list.add(()->{
		        long sum = 0L;
		    	for(Long i=2L;i<=n;i+=3) {
		    		sum += i;
		    	}
		    	return sum;
		    });
	     list.add(()->{
		        long sum = 0L;
		    	for(Long i=3L;i<=n;i+=3) {
		    		sum += i;
		    	}
		    	return sum;
		    });
	   List<Future<Long>> end =null;
	     try {
			end = exect.invokeAll(list);
			for(Future<Long> t:end) {
				value += t.get();
			}
		} catch (InterruptedException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
	     exect.shutdownNow();
	     System.out.println("this end is " + value);
	     return value;  
	 }
	 

	 public static void main(String[] args) throws ExecutionException {
		 Long start1 =  System.currentTimeMillis();
		 execSingle(3800000000L);
		 Long end1 =  System.currentTimeMillis();
		 System.out.println("单线程下:end1 - start1 = " +(end1-start1) );
		 Long start2 =  System.currentTimeMillis();
		 execMult(3800000000L);
		 Long end2 =  System.currentTimeMillis();
		 System.out.println("多线程下:end2 - start2 = " +(end2-start2) );
		 Long start3 =  System.currentTimeMillis();
		 ForkJoinPool pool = new ForkJoinPool();
		 ForkDemo demo = new ForkDemo(0L, 3800000000L);
		 ForkJoinTask<Long> task = pool.submit(demo);
		 Long end3 =  System.currentTimeMillis();
		 System.out.println("forkjoin框架下:end3 - start3 = " +(end3-start3) );
		 try {
			System.out.println(task.get());
		} catch (InterruptedException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
		 
	}
}

  最后控制台输出:(ForkJoin 优秀啊.....此处向大神Doug Lea模拜......)

注意ForkJoin需要使用合理的细分程度,这里多线程计算时间夸张了点.....具体情境还是要具体分析,有些情况多线程不一定比多线程快(有线程切换的代价),多线程需要互不依赖,如爬取图片,以此我也不知道....多线程花了这么多时间,哪位大佬给分下.....

 

posted @ 2019-06-04 17:57  林冲—first  阅读(861)  评论(0编辑  收藏  举报