Python内置函数(56)——locals

 英文文档:

locals()

Update and return a dictionary representing the current local symbol table. Free variables are returned by locals()when it is called in function blocks, but not in class blocks.

   返回当前作用域内的局部变量和其值组成的字典

说明:

  1. 函数功能返回当前作用域内的局部变量和其值组成的字典,与globals函数类似(返回全局变量)

>>> locals()
{'__package__': None, '__loader__': <class '_frozen_importlib.BuiltinImporter'>, '__doc__': None, '__name__': '__main__', '__builtins__': <module 'builtins' (built-in)>, '__spec__': None}

>>> a = 1

>>> locals() # 多了一个key为a值为1的项
{'__package__': None, '__loader__': <class '_frozen_importlib.BuiltinImporter'>, 'a': 1, '__doc__': None, '__name__': '__main__', '__builtins__': <module 'builtins' (built-in)>, '__spec__': None}

  2. 可用于函数内。

>>> def f():
    print('before define a ')
    print(locals()) #作用域内无变量
    a = 1
    print('after define a')
    print(locals()) #作用域内有一个a变量,值为1

    
>>> f
<function f at 0x03D40588>
>>> f()
before define a 
{} 
after define a
{'a': 1}

  3. 返回的字典集合不能修改。

>>> def f():
    print('before define a ')
    print(locals()) # 作用域内无变量
    a = 1
    print('after define a')
    print(locals()) # 作用域内有一个a变量,值为1
    b = locals()
    print('b["a"]: ',b['a']) 
    b['a'] = 2 # 修改b['a']值
    print('change locals value')
    print('b["a"]: ',b['a'])
    print('a is ',a) # a的值未变

    
>>> f()
before define a 
{}
after define a
{'a': 1}
b["a"]:  1
change locals value
b["a"]:  2
a is  1
>>> 
posted @ 2017-12-29 16:35  lincappu  阅读(193)  评论(0编辑  收藏